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Solnce55 [7]
3 years ago
5

Answer this if you want to be the brain list master ​

Mathematics
2 answers:
mojhsa [17]3 years ago
8 0

Answer:

3,240 / 9= 360\

360 boxes

Step-by-step explanation:

Thepotemich [5.8K]3 years ago
6 0

Answer:

360 boxes were used.

Step-by-step explanation:

You might be interested in
Alex bikes 2 3/4 miles. Then, she runs 1 2/4 miles. The distance she bikes is how many times the distance she runs?
Svet_ta [14]

Answer:

1.83 times

Step-by-step explanation:

Take the distance biked divided by the distance run.

2 3/4 / 1.5 = 1.83 times.

This means that Alex biked 1.83 times more than the distance she ran.

If this answer is correct, please make me Brainliest!

4 0
3 years ago
1)simplify the expression (2x)^4 2)the perimeter of a rectangular is twice the sum of its length and its width. the perimeter is
Marta_Voda [28]
(2x)^4=16x^4
------------------------------------------
2(l+w)=16\\
l=2w+2\\\\
2(2w+2+w)=16\\
6w+4=16\\
6w=12\\
w=2\\\\
l=2\cdot2+2\\
l=6

-------------------------------------------
-3+yi=x+6i\Rightarrow x=-3 \wedge y=6
5 0
3 years ago
A random sample of n = 45 observations from a quantitative population produced a mean x = 2.5 and a standard deviation s = 0.26.
oee [108]

Answer:

P-value (t=2.58) = 0.0066.

Note: as we are using the sample standard deviation, a t-statistic is appropiate instead os a z-statistic.

As the P-value (0.0066) is smaller than the significance level (0.05), the effect is  significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the population mean μ exceeds 2.4.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the population mean μ exceeds 2.4.

Then, the null and alternative hypothesis are:

H_0: \mu=2.4\\\\H_a:\mu> 2.4

The significance level is 0.05.

The sample has a size n=45.

The sample mean is M=2.5.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=0.26.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{0.26}{\sqrt{45}}=0.0388

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{2.5-2.4}{0.0388}=\dfrac{0.1}{0.0388}=2.58

The degrees of freedom for this sample size are:

df=n-1=45-1=44

This test is a right-tailed test, with 44 degrees of freedom and t=2.58, so the P-value for this test is calculated as (using a t-table):

P-value=P(t>2.5801)=0.0066

As the P-value (0.0066) is smaller than the significance level (0.05), the effect is  significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the population mean μ exceeds 2.4.

7 0
3 years ago
Please answer quickly! will give brainliest!
Y_Kistochka [10]

Answer:

12 cows and 5 chickens

8 0
2 years ago
Helppppp can someone answer these questions please ​
Delvig [45]

Answer:

Can you please tell us your question? Thanks!stiona

Step-by-step explanation:

4 0
3 years ago
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