Answer:
y=-1/3x-17/3
Step-by-step explanation:
I assume you mean <em>perpendicular</em><em> </em>to x=-3.
In that case, we would flip and take the negative. A perpendicular slope would be x=-1/3
Now we plug the point (4,-7) into the equation
y=mx+b
y=-1/3x+b
-7=-1/3*4+b
-7=-4/3+b
b= -17/3
The whole equation would be:
y=-1/3x-17/3
<em>I hope this helps! :)</em>
u(x) = -2x², v(x)= 1/x
(u o v)(x) = u(v(x)) = -2(1/x)²= -2/x²
We can see that domain for x is going to bee all real numbers except 0. From the equation above we can see that graph of the function (u o v)(x) = -2/x² has horizontal asymptote y=0, because degree of numerator is less than degree of denominator ( (u o v)(x) = -2x⁰/x² ).
x² is always going to be positive, so range is going to be all negative numbers.
y<0, or y∈(0,-∞)
Answer:
y=-12.5
Step-by-step explanation:
2y=-25
y=-12.5