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dalvyx [7]
3 years ago
13

If f(x) = 1/2x-14,then f^-1(x)=

Mathematics
2 answers:
Contact [7]3 years ago
5 0
The answer to your problem would be F ^-1 (x) = 2x + 28
Alik [6]3 years ago
4 0

Answer:

f ^-1 (x) = 2x+28

Step-by-step explanation:

f(x) = 1/2x-14

Replace f(x) with y

y = 1/2 x -14

Exchange x and y

x = 1/2 y -14

Solve for y

Add 14 to each side

x+14 = 1/2 y -14+14

x+14 = 1/2 y

Multiply each side by 2

2(x+14)= 1/2 y*2

2x+28 = y

The inverse function is

f ^-1 (x) = 2x+28

You might be interested in
a cylinder and a cone have the same radius and height. The volume of the cylinder is 534ft3 . what volume of the cone?
DochEvi [55]

Answer: 178 ft^3

Step-by-step explanation:

A cylinder has the formula V=pi radius ^2 height

A cone has the formula V= 1/3 pi radius ^2 height

So 1/3 of the volume of the cylinder is the volume of a cone

1/3 of 534 = 178 ft^3

5 0
2 years ago
What is the value of x in the equation (5^x)^5=5^35
Arada [10]

\bf (5^x)^5=5^{35}\implies 5^{x\cdot 5}=5^{35}\impliedby \begin{array}{llll} \textit{same bases}\\ \textit{same exponents} \end{array}\implies 5x = 35 \\\\\\ x = \cfrac{35}{5}\implies x=7

6 0
3 years ago
Find f(-2) for the following function. <br><br>f(x)=3.6x-2​
butalik [34]

Answer:

f(- 2) = - 9.2

Step-by-step explanation:

To evaluate f(- 2) substitute x = - 2 into f(x) , that is

f(- 2) = 3.6(- 2) - 2 = - 7.2 - 2 = - 9.2

4 0
3 years ago
I forgot how to do this, can sm1 solve it?​
STatiana [176]

Answer:

See below.

Step-by-step explanation:

Polly has the least. Let's work this from least to greatest.

They have £270. They share it together. Polly has £30. Andy has £60, and Phoebe has £180.

180 + 60 = 240.

240 + 30 = 270.

Pho: £180

Andy: £60

Polly: £30.

hope this helps.

3 0
3 years ago
Read 2 more answers
Iv)<br>6x+3y=6xy<br>2x + 4y= 5xy​
Margaret [11]

Answer:

Ok, we have a system of equations:

6*x + 3*y = 6*x*y

2*x + 4*y = 5*x*y

First, we want to isolate one of the variables,

As we have almost the same expression (x*y) in the right side of both equations, we can see the quotient between the two equations:

(6*x + 3*y)/(2*x + 4*y) = 6/5

now we isolate one off the variables:

6*x + 3*y = (6/5)*(2*x + 4*y) =  (12/5)*x + (24/5)*y

x*(6 - 12/5) = y*(24/5  - 3)

x = y*(24/5 - 3)/(6 - 12/5) = 0.5*y

Now we can replace it in the first equation:

6*x + 3*y = 6*x*y

6*(0.5*y) + 3*y = 6*(0.5*y)*y

3*y + 3*y = 3*y^2

3*y^2 - 6*y = 0

Now we can find the solutions of that quadratic equation as:

y = \frac{6 +- \sqrt{(-6)^2 - 4*3*0} }{2*3} = \frac{6 +- 6}{6}

So we have two solutions

y = 0

y = 2.

Suppose that we select the solution y = 0

Then, using one of the equations we can find the value of x:

2*x + 4*0 = 5*x*0

2*x = 0

x = 0

(0, 0) is a solution

if we select the other solution, y = 2.

2*x + 4*2 = 5*x*2

2*x + 8 = 10*x

8 = (10 - 2)*x = 8x

x = 1.

(1, 2) is other solution

8 0
3 years ago
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