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mr_godi [17]
3 years ago
10

Express the interval set builder notation

Mathematics
1 answer:
Ivenika [448]3 years ago
7 0

Answer:

{x | -1 < x ≤ 2}

Step-by-step explanation:

Interval given in the notation of (a, b) denotes,

Upper limit at 'b' and lower limit at 'a'

Sign () denotes the interval between a and b exclusive of the numbers a and b.

Interval given as [a, b] represents,

a = lower limit

b = higher limit

Notation of [] show the interval inclusive of these numbers.

Given set in the question is (-1, 2]

Here (-1) is the lower limit and 2 is the upper limit.

(] notation shows exclusive of (-1) and inclusive of 2.

Therefore, solution set in set-builder notation will be {x | -1 < x ≤ 2}

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Rewrite the following number as a power : 64
NISA [10]

Answer:

2^6

Step-by-step explanation:

What I did was multiply 2 by 2 as many times as it took to get to 64 since 2 is a multiplicity of 64

7 0
3 years ago
Please help me!!!!!!!!!
ASHA 777 [7]
Fraction=  x/6

x=numerator

x/6=1/3
x=6(1/3)
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answer:  2/6

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8 0
3 years ago
Escribe 2 ejemplos de enunciados que establezcan una regla de correspondencia que represente una función y
Annette [7]

Answer:

Correspondencia entre conjuntos:

a) Inyectiva: es cuando a cada imagen en el conjunto de llegada le corresponde un único origen, es decir, a distintos elementos del conjunto inicial, les corresponden distintos elementos del conjunto final.

b) Sobreyectiva: es si todos los elementos del conjunto final tienen al menos una correspondencia del conjunto inicial

c) Biyectiva: es cuando la correspondencia es inyectiva y sobre inyectiva a la vez

Correspondencia unívoca : es una correspondencia donde cada elemento del conjunto origen se corresponde con solo un elemento del conjunto de llegada.

Correspondencia biunívoca  es cuando a cada elemento del conjunto origen se corresponde con solo un elemento del conjunto llegada, y viceversa

Step-by-step explanation:

4 0
3 years ago
The equation of a circle is x2+y2−12x+6y+20=0 .
Rufina [12.5K]

Answer:

The radius is r=5 units

Step-by-step explanation:

we know that

The equation of the circle in standard form is equal to

(x-h)^{2}+(y-k)^{2}=r^{2}

where

(h,k) is the center and r is the radius

we have

x^{2}+y^{2}-12x+6y+20=0

Convert to standard form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(x^{2}-12x)+(y^{2}+6y)=-20

Complete the square twice. Remember to balance the equation by adding the same constants to each side

(x^{2}-12x+36)+(y^{2}+6y+9)=-20+36+9

(x^{2}-12x+36)+(y^{2}+6y+9)=25

Rewrite as perfect squares

(x-6)^{2}+(y+3)^{2}=5^{2}

therefore

The center is the point (6,-3) and the radius is r=5 units

8 0
3 years ago
Let f(x)=5x and g(x)= -x+1. Find f o g(ONLY 2 HOURS TO ANSWER!)
julia-pushkina [17]

Answer:  (b) -5x + 5

<u>Step-by-step explanation:</u>

f(x) = 5x        g(x) = -x + 1

f(g(x)): g(x) = -x + 1          f(-x + 1) = 5(-x + 1)

                                                   = -5x + 5

8 0
3 years ago
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