The answer to this query is AA similarity postulate. <span>
<span>Because the triangles given are only similar in angle but
dissimilar in sides which makes it incongruent with respect to the sides, AA
similarity postulate is the exact answer.
SAS ASA are not possible answers. </span></span>
|–2x| = -6
=> 2x = 6
=> x = 3
and,
=> 2x = -6
=> x = -3.
Two points, one at negative 3 and one at 3.
Hello :
<span>the equation is :
y - 90 = 15(x - 5)</span>
The correct answer is D
The equation of a circle is (x-h)^2 + (y-k)^2 = r^2
to find (h,k), you find the middle of the circle, in this scenario you do so by finding the middle of the diameter, a line that goes through the center of the circle.
To find the X value of the midpoint, add both x values together and divide by 2 and repeat for y
-13 + -1 = -14
-14/2 =-7
10+ -6 = 4
4/2 = 2
therefore (h,k) = ( -7, 2 )
Next plug these values in the equation of a circle
(x-h)^2 + (y-k)^2 = r^2
becomes
(x- (-7)) ^2 + (y-(2)) ^2 = r^2
to find r, use the distance formula to find the length of the diameter, 20, and divide by 2
plug 10 in for r and you get 100
(x+7)^2 + (y-2)^2 = 100
sorry for the late response
I think C is the correct answer. Have a good day : )
