Answer:
The diagram of the plotting point
is attached below.
Step-by-step explanation:
Given the points
![\left(3\frac{1}{2},\:2\frac{3}{4}\right)](https://tex.z-dn.net/?f=%5Cleft%283%5Cfrac%7B1%7D%7B2%7D%2C%5C%3A2%5Cfrac%7B3%7D%7B4%7D%5Cright%29)
as
![3\frac{1}{2}=\frac{7}{2}=3.5](https://tex.z-dn.net/?f=3%5Cfrac%7B1%7D%7B2%7D%3D%5Cfrac%7B7%7D%7B2%7D%3D3.5)
![2\frac{3}{4}=\frac{11}{4}=2.75](https://tex.z-dn.net/?f=2%5Cfrac%7B3%7D%7B4%7D%3D%5Cfrac%7B11%7D%7B4%7D%3D2.75)
so the point can be visualized as:
![\left(3\frac{1}{2},\:2\frac{3}{4}\right)=\left(3.5,\:2.75\right)](https://tex.z-dn.net/?f=%5Cleft%283%5Cfrac%7B1%7D%7B2%7D%2C%5C%3A2%5Cfrac%7B3%7D%7B4%7D%5Cright%29%3D%5Cleft%283.5%2C%5C%3A2.75%5Cright%29)
Now, we can check the point x = 3.5, and determine the corresponding value y = 2.75 and plot the point at the location (x, y) = (3.5, 2.75)
The diagram of the plotting point
is attached below.
Answer:
troll
Step-by-step explanation:
troll!!!!!!!!!!!!!!!!!!!!!!
Answer:
P(B) = 0.65
Step-by-step explanation:
We use the conditional probability formula to solve this question. It is
![P(B|A) = \frac{P(A \cap B)}{P(A)}](https://tex.z-dn.net/?f=P%28B%7CA%29%20%3D%20%5Cfrac%7BP%28A%20%5Ccap%20B%29%7D%7BP%28A%29%7D)
In which
P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
![P(A) = 0.26, P(B|A) = 0.65](https://tex.z-dn.net/?f=P%28A%29%20%3D%200.26%2C%20P%28B%7CA%29%20%3D%200.65)
They are independent events, which means that
. So
![P(B|A) = \frac{P(A \cap B)}{P(A)}](https://tex.z-dn.net/?f=P%28B%7CA%29%20%3D%20%5Cfrac%7BP%28A%20%5Ccap%20B%29%7D%7BP%28A%29%7D)
![0.65 = \frac{P(A)*P(B)}{P(A)}](https://tex.z-dn.net/?f=0.65%20%3D%20%5Cfrac%7BP%28A%29%2AP%28B%29%7D%7BP%28A%29%7D)
![P(B) = \frac{0.65P(A)}{P(A)}](https://tex.z-dn.net/?f=P%28B%29%20%3D%20%5Cfrac%7B0.65P%28A%29%7D%7BP%28A%29%7D)
![P(B) = 0.65](https://tex.z-dn.net/?f=P%28B%29%20%3D%200.65)
Answer:
Composite a aa a a a a a a a a a a a a a a a a a a a a a a aaaaaaaaaaaaaaa
Answer:
The probability that a contestant who plays the game five times wins exactly twice is
%
Step-by-step explanation:
We will use binomial theorem here
![C_{n,k}p^k(p')^{n-k}](https://tex.z-dn.net/?f=C_%7Bn%2Ck%7Dp%5Ek%28p%27%29%5E%7Bn-k%7D)
Substituting the available values in above equation, we get
![C_{5,2} * \frac{1}{6}^2*\frac{5}{6}^3](https://tex.z-dn.net/?f=C_%7B5%2C2%7D%20%2A%20%5Cfrac%7B1%7D%7B6%7D%5E2%2A%5Cfrac%7B5%7D%7B6%7D%5E3)
![0.1608](https://tex.z-dn.net/?f=0.1608)
OR
The probability that a contestant who plays the game five times wins exactly twice is
%