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4 years ago

Which type of number is 12

Mathematics

2 answers:

telo118 [61]4 years ago

4 0

Answer:

Composite a aa a a a a a a a a a a a a a a a a a a a a a a aaaaaaaaaaaaaaa

Natali5045456 [20]4 years ago

4 0

Answer:

its composite

Step-by-step explanation:

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URGENT PLEASE HELP ME !!!

Marrrta [24]

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3 years ago

How do I write the ratio of 28 inches to 5 feet as a fraction in simplest form?

stich3 [128]

Step 1. Divide denominator to numerator .

Step 2. you should have 5.4

Step 3. Keep the denominater (5) and add 5.4 as your numerator.

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3 years ago

An experiment has four equally likely outcomes: E1, E2, Es, and E.Round your answers to three decimal places. a. What is the pro

V125BC [204]

Answer:

a. 0.25

b. 0.50

c. 0.75

Step-by-step explanation:

P(E1) = 0.25

P(E2) = 0.25

P(Es) = 0.25

P(E) = 0.25

a. Since there are 4 outcomes with the same probability of occurring, the probability of E occurring is:

$P(E) = \frac{1}{4}=0.25$

b. The probability of any two outcomes occurring is twice the probability of a single outcome occurring

$P(two\ outcomes) = 2*P(one\ outcome) = \frac{2}{4}=0.50$

c. The probability of any three outcomes occurring can be written as 100% minus the probability of the remaining outcome occurring

$P(three\ outcomes) = 1-P(one\ outcome) = 1-\frac{1}{4}=0.75$

6 0

4 years ago

Solve using law of sines or law of cosines!

malfutka [58]

Answer:

Part 5) The length of the ski lift is $1.15\ miles$

Part 6) The height of the tree is 18.12 m

Step-by-step explanation:

Part 5)

Let

A -----> Beginning of the ski lift

B -----> Top of the mountain

C -----> Base of mountain

we have

$b=0.75\ miles$

$A=20\°$

$C=180\°-50\°=130\°$ ----> by supplementary angles

Find the measure of angle B

Remember that the sum of the interior angles must be equal to 180 degrees

$B=180\°-A-C$

substitute

$B=180\°-20\°-130\°=30\°$

Applying the law of sines

$\frac{b}{sin(B)}=\frac{c}{sin(C)}$

substitute

$\frac{0.75}{sin(30\°)}=\frac{c}{sin(130\°)}$

$c=\frac{0.75}{sin(30\°)}(sin(130\°))$

$c=1.15\ miles$

Par 6)

see the attached figure with letters to better understand the problem

Applying the law of sines in the right triangle BDC

In the right triangle BDC 20 degrees is the complement of 70 degrees

$\frac{BC}{sin(70\°)}=\frac{x}{sin(20\°)}$

$BC=(sin(70\°))\frac{x}{sin(20\°)}$ -----> equation A

Applying the law of sines in the right triangle ABC

In the right triangle ABC 50 degrees is the complement of 40 degrees

$\frac{BC}{sin(40\°)}=\frac{x+15}{sin(50\°)}$

$BC=(sin(40\°))\frac{x+15}{sin(50\°)}$ -----> equation B

Equate equation A and equation B and solve for x

$(sin(70\°))\frac{x}{sin(20\°)}=(sin(40\°))\frac{x+15}{sin(50\°)}\\\\2.7475x=0.8391(x+15)\\\\2.7475x=0.8391x+12.5865\\\\2.7475x-0.8391x=12.5865\\\\x=6.60\ m$