Answer:
Cost of one chair = Rs . 150
Cost of one table = Rs. 500
Step-by-step explanation:
Let number of chairs denote x and no of tables denote y
4x + 3y = 2100 --------------------(i)
5x +2y = 1750 ------------------(ii)
Multiply equation (i) by 2 and (ii) by (-3) and now y will be eliminated.
(i)*2 8x + 6y = 4200
(ii)*(-3) -<u>15x - 6y = - 5250</u> {Now, add}
- 7x = - 1050
x = -1050/-7
x = Rs. 150
Plug in the value of x inn equation (i)
4*150 + 3y = 2100
600 + 3y = 2100
3y = 2100 - 600
3y = 1500
y= 1500/3
y =Rs 500
Answer:
Step-by-step explanation:
6cos^2(x) + 7cos(x) +2 = 0
Call cos(x) = y to change this to something a little bit more familiar.
6y^2 + 7y + 2 =0
This equation is a quadratic. Solve it first. Then we'll go back to solving for cos(x)
This equation factors into 2 possible answers
(3y + 2)(2y + 1) = 0
3y + 2 = 0
3y = - 2
y = - 2/3
2y + 1 = 0
2y = - 1
y = - 1/2
Now let's start with
cos(x) = - 1/2
That means that x is in quadrant two or three.
cos-1(1/2) = 60 degrees.
Quad 2: x = 180 - 60 = 120
Quad 3: x = 180 + 60 = 240
Now cos(x) = - 2/3
cos-1(2/3) = 48.19
Quad 2: x = 180 - 48.19 = 131.81
Quad 3: x = 180 + 48.19 = 228.19
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Answer:
In the picture
Step-by-step explanation:
I hope that a clear explanation
Answer: 289/900
Explanation: I did this before
