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Arisa [49]
3 years ago
13

Evalute

i}{12}) " alt=" sin^2(\frac{\pi}{12}) " align="absmiddle" class="latex-formula">
A. 1/4
B. 3/4
C. \frac{2-\sqrt3}{4}}
D. \frac{2+\sqrt{3}}{4}

PLEASE HELP ME.
Mathematics
1 answer:
leonid [27]3 years ago
3 0
Use the double angle identity:


\sin^2\dfrac\pi{12}=\dfrac{1-\cos\frac\pi6}2


Then \cos\dfrac\pi6=\dfrac{\sqrt3}2, so you get


\sin^2\dfrac\pi{12}=\dfrac{2-\sqrt3}4
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