Answer:
29C3 = 3654
Step-by-step explanation:
What is applied here is combination that n - combination of r which is a subscript and the n - is a superscript.
- nCr = nPr/r!
- where nPr = n!/(n-r)!
- nCr = n!/(n-r)! r!
- And we are told to find 29C3, apply the formula and your results will be out.
Attached is the detailed explanation.
