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2 years ago

For what value of X is the rational expression below equal to zero?

Mathematics

1 answer:

Sophie [7]2 years ago

5 0

Answer:

Option D, x = 1

Step-by-step explanation:

In order for that equation to equal to zero, you need the numerator (the top) to equal zero and the denominator (the bottom) to equal literally anything BUT ZERO.

To satisfy the first part we set the top binomial equal to zero.

x - 1 = 0

x = 0 + 1

x = 1

Plug in x = 1 to the bottom to see if it satisfies to second part; we're looking for everything but zero.

(x - 3)(x + 1)

(1 - 3)(1 + 1)

(- 2)(2) = - 4

Your answer is x = 1, option D.

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A number r divided by 82

Natalija [7]

Answer:

574 is a number that can be divided by 82

6 0

3 years ago

The rectangle is 16 inches by 25 inches. If the scale is 4 in :5 ft what is the length and width of the rectangle in feet.

Alenkasestr [34]

Answer:

The length and width of the rectangle are 20 feet and 31.25 feet, respectively.

Step-by-step explanation:

Let the scale be $4\,in\,:\,5\,ft$ and the dimensions of the rectangle being 4 inches and 5 inches, respectively. The scale ( $r$ ), measured in inches per feet, is equivalent to the following rational number:

$r = \frac{4\,in}{5\,ft}$

We can convert each length by dividing it by scale factor. That is:

Length

$l' = \frac{16\,in}{\frac{4\,in}{5\,ft} }$

$l' = 20\,ft$

Width

$w' = \frac{25\,in}{\frac{4\,in}{5\,ft} }$

$w' = 31.25\,ft$

The length and width of the rectangle are 20 feet and 31.25 feet, respectively.

8 0

2 years ago

Which expression represents the distance between point (0, a) and point (a, 0) on a coordinate grid?

o-na [289]

Answer:

$\sqrt{2} a$

Step-by-step explanation:

The distance between point (x1,y1) and (x2,y2) on a coordinate plane is given by expression $\sqrt{(x1-x2)^2+(y1-y2)^2}$

In the problem given coordinate points are

(0, a) and (a, 0).

Thus, distance between these points are given by

$distance = \sqrt{(x1-x2)^2+(y1-y2)^2}\\=>distance = \sqrt{(0-a)^2+(a-0)^2}\\=>distance = \sqrt{(a)^2+(a)^2}\\\\=>distance = \sqrt{2a^2}\\=>distance = \sqrt{2} a$