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4 years ago

1. Vocabulary What operations have inverse relationships?

Mathematics

2 answers:

steposvetlana [31]4 years ago

4 0

Answer:

Addition and subtraction are inverse operations, Multiplication and division are inverse operations.Another pair of inverse mathematical operations is raising a number to an exponent "n" and taking the nth root of the number.

Vlada [557]4 years ago

3 0

Answer: In mathematics, an inverse operation is an operation that undoes what was done by the previous operation. The four main mathematical operations are addition, subtraction, multiplication, division. The inverse of addition is subtraction and vice versa. The inverse of multiplication is division and vice versa

Step-by-step explanation: hope this helps :)

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Find the value of x if a,b, and c are collinear points an b is between a and c

MakcuM [25]

$\sf Hello!$

• $\sf AB = x + 6$
• $\sf BC = 3x - 5$
• $\sf AC = 36 - x$

$\sf We're \:given\: that \:A,\: B\: and \:C \:are \:Collinear\: points$

$\sf Then,$

$\sf AB + BC = AC$

⇒ $\sf x + 6 + 3x - 5 = 36 - x$

⇒ $\sf x + 3x + 6 - 5 = 36 - x$

⇒ $\sf 4x + 1 = 36 - x$

⇒ $\sf 4x + x = 36 - 1$

⇒ $\sf 5x = 35$

⇒ $\sf x = \dfrac{\sf 35}{\sf 5}$

⇒ $\boxed{\sf x = 7}$

$\sf Hence,$

$\sf The\: value\: of\: x\: is\: D.\: 7$

~ $\sf iCarl$

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Use the discriminant to determine the number of solutions to the quadratic equation 3x^2+5x=-1

kari74 [83]

Answer:

Two real distinct solutions

Step-by-step explanation:

Hi there!

Background of the Discriminant

The discriminant $b^2-4ac$ applies to quadratic equations when they are organised in standard form: $ax^2+bx+c=0$ .

All quadratic equations can be solved with the quadratic formula: $x = \frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}}$ .

When $b^2-4ac$ is positive, it is possible to take its square root and end up with two real, distinct values of x.

When it is zero, we won't be taking the square root at all and we will end up with two real solutions that are equal, or just one solution.

When it is negative, it is impossible to take the square root and we will end up with two non-real solutions.

Solving the Problem

$3x^2+5x=-1$

We're given the above equation. It hasn't been organised completely in $ax^2+bx+c=0$ , but we can change that by adding 1 to both sides to make the right side equal to 0:

$3x^2+5x+1=0$