Answer:
A punnet square can be described as a diagram which is made to check the outcomes of a cross.
To check the probability of the offsprings of a cross between homozygous dominant thumb shape parent with a homozygous recessive thumb shape parent, let's draw a punnet square:
t t
T Tt Tt
T Tt Tt
The results of the punnet square depict that:
Genotype: All of the offsprings will be heterozygous for the thumb shape trait. Tt will be the genotype.
Phenotype: All of the offsprings will show the thumb shape like the thumb shape of the dominant parent.
The probability that their son exhibits the 'color blind' trait is 0%. It is a type of inheritance linked to the X chromosome.
<h3>Inheritance linked to the X chromosome</h3>
In men, the patterns of inheritance linked to the X chromosome don't follow conventional mendelian inheritance because men have only one X chromosome.
Conversely, women have two X chromosomes, thereby the inheritance pattern resembles Mendelian inheritance.
It is important to highlight that color blindness is a recessive trait on the X chromosome.
In this case, the mother is a carrier, thereby the probability of passing this trait as a carrier to her son is 50%, whereas the father is normal, thereby the probability of passing this trait to his son is 0%.
Learn more about inheritance linked to the X chromosome here:
brainly.com/question/1020249
The possible genotypes for the plant are Rr Rr rr rr. So there is a 0% chance
