Make an x and y table, and pick any values to plug in for x in the equation.
I will use the numbers from -2 to 2
Now plug in the values you picked for x into the equation to find its y-value
x = -2
y = 3x - 1 Plug in -2 for x
y = 3(-2) - 1
y = -6 - 1
y = -7
x = -1
y = 3x - 1
y = 3(-1) - 1
y = -3 - 1
y = -4
Do the same for the rest of the numbers, and graph each point and draw a line connecting them.
Answer:
Option B.
Step-by-step explanation:
The non-uniform probability is when the event is not same in the occurring of event.
Option A is uniform because there will be equal chance of getting head or tail.
Option B is non-uniform because sum can be any number if we get(3,4) it will be 7 and if we have (2,3) then it will be 5.
Option C is uniform because we have equal number of red and green balls so, selecting a ball from both will be same.
Option D is uniform because chance of 1,2,,3,4,5 or 6 will be equal chance from rolling a die that is 1/6 in all cases.
Therefore, Option B is correct
The answer is B) it shifts up and to the right
Perimeter simply represents the sum of all side lengths of a shape. The length of the missing side of the ticket is 5 cm; the length of gold line on each ticket is 20 cm, and 2 bottles of gold ink are required to draw gold lines on 200 tickets.
I've added the image of the ticket as an attachment.
(a) The missing side length
From the attachment, the 4 unknown side lengths are equal. Represent this side length with L.
So, we have:
This gives
Collect like terms
Divide both sides by 4
(b) The length of the gold lines
There are 4 slant lines and the length of one of the slant lines is 5 cm (as calculated above).
So, the length of the gold line is:
(c) The number of gold ink bottles.
--- number of tickets
The length of all gold line in the 200 tickets is:
---- convert to meters
Given that:
--- 1 bottle for 20 m
The number of bottles (n) is:
Hence, 2 bottles of gold ink are enough.
Read more about perimeters at:
brainly.com/question/6465134
Answer:
Step-by-step explanation:
Okay, so I think I know what the equations are, but I might have misinterpreted them because of the syntax- I think when you ask a question you can use the symbols tool to input it in a more clear way, otherwise you can use parentheses and such.
Problem 1:
(x²)/4 +y²= 1
y= x+1
*substitute for y*
Now we have a one-variable equation we can solve-
x²/4 + (x+1)² = 1
x²/4 + (x+1)(x+1)= 1
x²/4 + x²+2x+1= 1
*subtract 1 from both sides to set equal to 0*
x²/4 +x^2+2x=0
x²/4 can also be 1/4 * x²
1/4 * x² +1*x² +2x = 0
*combine like terms*
5/4 * x^2+2x+ 0 =0
now, you can use the quadratic equation to solve for x
a= 5/4
b= 2
c=0
the syntax on this will be rough, but I'll do my best...
x= (-b ± √(b²-4ac))/(2a)
x= (-2 ±√(2²-4*(5/4)*(0))/(2*(5/4))
x= (-2 ±√(4-0))/(2.5)
x= (-2±2)/2.5
x will have 2 answers because of ±
x= 0 or x= 1.6
now plug that back into one of the equations and solve.
y= 0+1 = 1
y= 1.6+1= 2.6
Hopefully this explanation was enough to help you solve problem 2.
Problem 2:
x² + y² -16y +39= 0
y²- x² -9= 0
