All categories

2 years ago

What is 0.947 in word form

Mathematics

2 answers:

Bond [772]2 years ago

8 0

Zero point nine hundred and fourteen seven

^_^

Hope this helps you!

xz_007 [3.2K]2 years ago

6 0

0.947 in word form is zero point nine hundred and forty seven

You might be interested in

Question 1

Scrat [10]

Answer:

17.11 meters

Step-by-step explanation:

You are using trigonometry in this problem.

The height of the flagpole represents the side opposite the given angle.

The base of the triangle is given as 19 meters and represents the side adjacent to the given angle.

Out of the main trigonomentric functions (sine, cosine, and tangent), only tangent uses both the opposite and adjacent sides.

Tan(angle) = opposite / adjacent

If we plug in what we know into that equation: tan(42 degrees) = h / 19

This means that your answer = 19 * tan(42) = 17.11 meters

6 0

2 years ago

What is the area of a triangle that has a height of 12 feet and a base length of 6 feet? 24 feet2 36 feet2 48 feet2 72 feet2

Kaylis [27]

It is 36 feet
A=1/2bh
a=1/2*12*6
a=6*6
a=36feet squared
hope this helps!

8 0

3 years ago

Read 2 more answers

What is the equation for the vertical asymptote of the function shown below? f(x)=3x^4-3/2x-5

levacccp [35]

$f(x)= \frac{3x^4}{2x-5}$

the va's are where x is undefined, or where the denomenator is zero
first simplify if applicable
cannot simplify

set denom to zero
2x-5=0
2x=5
x=2.5

the vertical assemtote is vertical so it is x=2.5 or 5/2

the VA is x=5/2

3 0

3 years ago

Integration by Parts Evaluate e-2x cos(2x) dx.

kifflom [539]

Let

$I = \displaystyle \int e^{-2x} \cos(2x) \, dx[/]texIntegrate by parts:[tex]\displaystyle \int u \, dv = uv - \int v \, du$

with

$u = e^{-2x} \implies du = -2 e^{-2x} \, dx \\\\ dv = \cos(2x) \, dx \implies v = \dfrac12 \sin(2x)$

Then

$\displaystyle I = \frac12 e^{-2x} \sin(2x) + \int e^{-2x} \sin(2x) \, dx + C$

Integrate by parts again, this time with

$u = e^{-2x} \implies du = -2 e^{-2x} \, dx \\\\ dv = \sin(2x) \, dx \implies v = -\dfrac12 \cos(2x)$

so that

$\displaystyle I = \frac12 e^{-2x} \sin(2x) - \frac12 e^{-2x} \cos(2x) - \int e^{-2x} \cos(2x) \, dx + C\\\\ \implies I = \frac{\sin(2x)-\cos(2x)}{2e^{2x}} - I + C \\\\ \implies 2I = \frac{\sin(2x) - \cos(2x)}{2e^{2x}} + C \\\\ \implies I = \boxed{\frac{\sin(2x) - \cos(2x)}{4e^{2x}} + C}$

6 0

1 year ago

Divide the sum of 8 and 12 by 4

Nonamiya [84]

Answer:

12+4/8

Step-by-step explanation:

sum means add and you need to divide 8 by whatever 12 and 4 equal

12+4= 16

16/8=2

8 0

3 years ago

Read 2 more answers