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ahrayia [7]
3 years ago
10

Milton makes trail mix for his hiking group he makes a 1 and 1/4 pound of peanuts 14 oz of raisins 12 oz of walnuts in 10 oz of

chocolate chips to melt in The Vibes the trail mix among the eight hikers in the group how many ounces of trail bikes does each hiker receive remember there are 16 oz in one pound
Mathematics
1 answer:
strojnjashka [21]3 years ago
8 0

Answer:

Each hiker receives 7 ounces of trail mix

Step-by-step explanation:

Trail mix=quantity of peanuts+quantity of raisins+quantity of walnuts+quantity of chocolate chips

where;

Quantity of peanuts=1.25 pounds

Quantity of raisins=14 oz, since 1 pound=16 oz.

Quantity of raisins=(14/16)=0.875 pounds

Quantity of walnuts=12 oz=(12/16)=0.75 pounds

Quantity of chocolate chips=10 oz=(10/16)=0.625 pounds

Replacing;

Trail mix=(1.25+0.875+0.75+0.625)=3.5 pounds

Trail mix=Quantity per hiker×Number of hikers

where;

Trail mix=3.5 pounds

Quantity per hiker=q

Number of hikers=8

Replacing;

3.5=q×8

q=3.5/8=0.4375 pounds

I pound=16 ounces

q=0.4375×16=7 ounces

Each hiker receives 7 ounces of trail mix

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Answer:

A. Sample Space = S = {(9, 18),(9, 19),(9, 20),(9, 21),(10, 18),(10, 19),(10, 20),(10, 21),(11, 18),(11, 19),(11, 20),(11, 21),(12, 18),(12, 19),(12, 20),(12, 21)}

B.  {(9, 18),(10, 18),(11, 18),(12, 18)}

C. {(9, 18),(9, 19),(10, 18)}

D.  {(9, 18),(9, 19),(10, 18),(11, 18),(12, 18)}

E. B(complement) ∩C =  {(9, 19)}

Step-by-step explanation:

The Sample Space would contain each element of the box A associated with each element of the box B.

A. Sample Space = S = {(9, 18),(9, 19),(9, 20),(9, 21),(10, 18),(10, 19),(10, 20),(10, 21),(11, 18),(11, 19),(11, 20),(11, 21),(12, 18),(12, 19),(12, 20),(12, 21)}

B.  Let the Outcomes in the event B, the event that the second resistor has a resistance less than 19 be denoted by J then

J=  {(9, 18),(10, 18),(11, 18),(12, 18)}

C. Let the outcomes in the event C, the event that the sum of the resistances is equal to 28 be denoted by L then

L =  {(9, 18),(9, 19),(10, 18)}

D. The  outcomes in B∪C contains all the elements of B and C

B∪C=J∪L= {(9, 18),(9, 19),(10, 18),(11, 18),(12, 18)}

E. B complement contains those elements of the Sample Space which are not the elements of Set B.

B complement= S-B=  {(9, 19),(9, 20),(9, 21),(10, 19),(10, 20),(10, 21),(11, 19),(11, 20),(11, 21),(12, 19),(12, 20),(12, 21)}

B(complement) ∩C contains those elements of B and C which are common to both B complement and C.

B(complement) ∩C =  {(9, 19)}

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