Slope point form :
To put in slope point form, label any of the points as either X1,y1 and X and y, then plug in those values into the following equation form.
Y - y1 = m(X-X1)
But before, we must solve for the m value or slope.
M = y2-y1/x2-X1
M = 5/2 - -1/2 / -1/2 - 3/2.
M = 5/2 + 1/2 / -(1/2+3/2)
M = 6/2 / -(4/2)
M = 3/-2
Now we can place it in slope point and also in standard form of a line.
Y-y1 = m(X -X1)
Y - -1/2 = -3/2(X - 3/2)
Y + 1/2 = -3/2(X - 3/2)
This is in slope point form.
Y + 1/2 = -3/2x + 9/4
Y + 1/2 - 1/2 = -3/2x + 9/4 - 1/2
1/2 = 2/4
Y = -3/2x + 7/4
-3/2x = -6/4x
Y = -6/4x + 7/4
Y • 4 = 4( -6/4 X + 7/4)
4y = -6x + 7
4y + 6x = -6x + 6x +7
6x + 4y = 7
This is in standard form. If you have any questions of the steps just ask.
Answer:
SinL = 7/25
CosL = 24/25
TanL = 7/24
Step-by-step explanation:
Find the diagram attached.
Using SOH CAH TOA in trigonometry identity to find the sinL, cosL and TanL
Note that the hypotenuse is the longest side = 25
The opposite will be the side facing the acute angle L
Opposite = 7
Adjacent = 24
For SinL
sinL = Opposite/Hypotenuse {SOH}
SinL = 7/25
For cosL:
CosL = Adjacent/Hypotenuse{CAH}
CosL = 24/25
For tanL:
TanL = Opposite/Adjacent {TOA}
TanL = 7/24
Answer: 8 1/3 hours or 500 minutes
Step-by-step explanation:
Keep in mind that there are 100 centimeters in a meter.
The snail moves at a pace of 12 cm/h, and needs to go 100 cm. You can just divide 100/12 to get 8 1/3, which is how many hours (groups of 12 cm) it takes for the snail to travel 100 cm (1 meter).
If necessary, you can also multiply 8 1/3 by 60 to get the number of minutes the snail takes. 8 times 60 is 480, and 1/3 of an hour is 20, so add 480+20 to get 500 minutes.
Answer: 13.2
Step-by-step explanation:
the ratio between the given measurements (11 and 5) is 2.2 [5 x 2.2 = 11]
so, i just multiplied 6 by 2.2 , which equals 13.2 .
hope this helps! xoxo
