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4 years ago

Thanks for the help offering double points for this question not that its hard but that I need it in a hurry!

Mathematics

1 answer:

fredd [130]4 years ago

4 0

The first 1 is A Second 1 is d

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Multiply and simplify. 1/2 X (13/6+7/8

Andrej [43]

(12x)(136+78)=(12x)(136+78)=(12x)(136)+(12x)(78)=1312x+716x=7348x

8 0

3 years ago

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¿Cuáles son las principales diferencias entre ambos estudios?

Dafna11 [192]

Eudua fuire estuary

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3 years ago

Simplify the expression 4-2(7+9)+4

julia-pushkina [17]

Answer:

4-2(16)+4

Step-by-step explanation:

7 0

3 years ago

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Would anyone care to explain how to get through this problem in the photo? I'm at a complete dead end! Any help would be appreci

shutvik [7]

Step-by-step explanation:

The slope of the equation tangent to y = f(x) at x = 4 is equal to f'(4). Therefore,

$m = f'(4) = \dfrac{1}{(4)^2 - 9} = \dfrac{1}{7}$

We also know that the line passes through the tangent point at (4, -1) so we can write the slope-intercept form of the equation as

$y = mx + b \Rightarrow -1 = \dfrac{1}{7}(4) + b$ or

$b = -\dfrac{11}{7}$

so our equation is

$y = \dfrac{1}{7}x -\dfrac{11}{7}$

or in standard form,

$x - 7y = 11$

5 0

3 years ago

Write down an (in)equality which describes the solid ball of radius 2 centered at (-2, 5, 2). It should have a form like ????2 ?

MissTica

$\text{We know that the euation of the sphere with radius r and centered at (h,k,l)}\\
\text{is given by:}\\
\\
(x-h)^2+(y-k)^2+(z-l)^2=r^2\\
\\
\text{here we have given a solid ball of radius 2 centered at }(-2, 5,2), \text{ so the }\\
\text{region of the ball will be all the area within the ball.}\\
\text{Hence the inequality that will describe the ball is give given by}$

$(x-(-2))^2+(y-5)^2+(z-2)^2\leq 2^2\\
\\
\Rightarrow (x+2)^2+(y-5)^2+(z-2)^2\leq 4\\
\\
\text{hence the required inequality that describes the ball is:}\\
\\
(x+2)^2+(y-5)^2+(z-2)^2-4\leq 0$

6 0

4 years ago