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Westkost [7]
3 years ago
7

Simplify the problem

Mathematics
1 answer:
Natasha2012 [34]3 years ago
5 0
\frac{6}{10x^2} \div  \frac{6}{10x^3-60x^2}  = \frac{6}{10x^2} \cdot  \frac{10x^3-60x^2}{6}  =\frac{1}{10x^2} \cdot  \frac{10x^2(x-6)}{1}  =x-6
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In the radius of a circle with an area of 10 inches squared is reduced by half what is the area of the new circle
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