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Charra [1.4K]
3 years ago
10

In which model are atoms are imagined as the solar system

Physics
1 answer:
olga2289 [7]3 years ago
8 0

Answer: Bohr's model

Explanation:

 The Bohr's model is also known as the solar system model which describe that an atoms are basically imagine in the form of solar system. The Bohr's model basically describe about the atoms that it consist of nucleus with the number of electron in an orbit by using the electrostatic attraction.

The Bohr's model are introduced for overcoming the drawback in the Rutherford model as he proposed an idea that at different energy levels the electron can revolve in certain orbits around nucleus.  

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What is the Calvin cycle and why is it essential for the transfer of energy during photosynthesis
timurjin [86]
Calvin Cycle is the part of the process of photosynthesis, by which Plant makes Food (Glucose), it is independent of the light. It is essential as it is the primary source of energy on the earth

Hope this helps!
8 0
4 years ago
Read 2 more answers
Determine the molar concentration of 4 moles of HCL dissolved in 2500 ml of solution​
Reptile [31]

Answer:

1.6 molar

Explanation:

C=number of moles/volume

convert ml to L

V =2.5L

C= 4/2.5

=1.6 molar

4 0
1 year ago
A current of 0.92 a flows in a wire. how many electrons are flowing past any point in the wire per second? the charge on one ele
Fantom [35]
The current is defined as the ratio between the charge Q flowing through a certain point of a wire and the time interval, \Delta t:
I= \frac{Q}{\Delta t}
First we need to find the net charge flowing at a certain point of the wire in one second, \Delta t=1.0 s. Using I=0.92 A and re-arranging the previous equation, we find
Q=I \Delta t= (0.92 A)(1.0 s)=0.92 C

Now we know that each electron carries a charge of e=1.6 \cdot 10^{-19} C, so if we divide the charge Q flowing in the wire by the charge of one electron, we find the number of electron flowing in one second:
N= \frac{Q}{q} = \frac{0.92 C}{1.6 \cdot 10^{-19} C}=5.75 \cdot 10^{18}
3 0
3 years ago
In one scene in the movie The Godfather II, a solid gold phone is passed around a large table for everyone to see. Suppose the v
dangina [55]
Volume of gold in the phone = 10 cm^3
                                              = 0.<span>00001 m^3 </span>
Density of gold = 19300 kg/m^3
1 kg mass = 2.2 pounds
Mass of 10 cm^3 of gold = 0<span>.00001 m^3 * (19300 kg/m^3)
                                        = 0.193 kg 
So
0.193 kg = 0.193 * 2.2 pounds
               = 0.43 pounds
I think there is something wrong with the options given in the question.</span>
7 0
4 years ago
What is the magnitude of the momentum of a 33 g sparrow flying with a speed of 8.7 m/s?
WARRIOR [948]

Answer:

0.2871 kg m/s

Explanation:

p = mv

convert 33g into kg (0.033)

mulitply byt 8.7 to get 0.2871

4 0
3 years ago
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