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3 years ago

What two factors determine the force of gravity between two objects?

Physics

1 answer:

Yuki888 [10]3 years ago

5 0

Answer:

Mass and distance between them are two factors on which force of gravity depends

Explanation:

According to law of gravitation

Gravitational force between two object is given by $F=\frac{Gm_1m_2}{r^2}$ , here G is gravitational constant $m_1\ and\ m_2$ are mass of the objects and r is distance between them

From the relation we can see that force of gravity is dependent on the mass of the objects and distance between them.

So mass and distance between them are two factors on which force of gravity depends

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Irina-Kira [14]

Answer:

Explanation:

We know that Impulse = force x time

impulse = change in momentum

change in momentum = force x time

Force F = .285 t -.46t²

Since force is variable

change in momentum = ∫ F dt where F is force

= ∫ .285ti - .46t²j dt

= .285 t² / 2i - .46 t³ / 3 j

When t = 1.9

change in momentum = .285 x 1.9² /2 i - .46 x 1.9³ / 3 j

= .514i - 1.05 j

final momentum

= - 3.1 i + 3.9j +.514i - 1.05j

= - 2.586 i + 2.85j

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y component = 2.85

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3 years ago

An artillery shell is launched on a flat, horizontal field at an angle of α = 40.8° with respect to the horizontal and with an i

Lina20 [59]

Answer:

1317.4 m

Explanation:

We are given that

Angle= $\alpha=40.8^{\circ}$

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We have to find the horizontal distance covered by the shell after 5.03 s.

Horizontal component of initial speed= $v_{ox}=v_0cos\theta=346cos40.8=261.9m/s$

Vertical component of initial speed= $v_{oy}=346sin40.8=226.1m/s$

Time=t=5.03 s

Horizontal distance = $Horizontal\;velocity\times time$

Using the formula

Horizontal distance= $261.9\times 5.03$

Horizontal distance=1317.4 m

Hence, the horizontal distance covered by the shell=1317.4 m

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Answer:

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Answer:

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