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CaHeK987 [17]
3 years ago
10

HELP ASAP! 20 POINTS! 10 QUESTIONS!

Mathematics
2 answers:
ser-zykov [4K]3 years ago
8 0

Answer:

Thanks!!!

Step-by-step explanation:

Snowcat [4.5K]3 years ago
7 0
1. B 2.C 3.B 4.C 5.B 6.A 7.A 8.D 9.B 10.C
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3.15x4.12=<br><img src="https://tex.z-dn.net/?f=3.15x4.12%20%3D%20" id="TexFormula1" title="3.15x4.12 = " alt="3.15x4.12 = " ali
gulaghasi [49]

Answer:

1/61.8 its right valu of x

Step-by-step explanation:

here we find the first valu and second is also same but there isx so cross the eqal side and get same answer

4 0
3 years ago
The probability that you roll a 5 on a six-sided die is start fraction one over six end fraction . the probability that you flip
Anastaziya [24]
Let event A be the coin landing on heads and let event B be rolling a 5 on a six-sided die.
Events A and B are independent if, and only if:
P(A\cap B)=P(A)\times P(B)
It is given in the question that the above condition for independence is met.
Also A and B are independent if:
P(A|B) = P(A)
P(A) = 1/2
Therefore the probability of flipping a coin and it landing on heads, given that you rolled a 5 on a six-sided die is 1/2. The two events are independent.
5 0
3 years ago
Jeff provides photos for two online sites: site A and site B.
Setler [38]
$0.25 you just have to multiply .65 times 5 for site A which is $3.25 and for sure b just plug in 5 for x and multiply by .60 which gives you $3.00 so site A gives you $0.25 more
5 0
3 years ago
Read 2 more answers
Determine whether the following are subspaces of R2×2 : (a) Thesetofall2×2diagonalmatrices (b) The set of all 2 × 2 triangular m
Mrrafil [7]

A vector space V is a subspace of a vector space W if

  • V is non-empty,
  • for any two vectors v_1,v_2\inV we have v_1+v_2\in V, and
  • for any scalar k and v\in V we have kv\in V.

It's easy to show the first condition is met by all the sets in parts (a-g).

(a) is a subspace of \Bbb R^{2\times2} because adding any 2x2 diagonal matrices together, or multiplying one by some scalar, gives another diagonal matrix.

(b) and (c) are also subspaces for the same reasons.

(d) is not a subspace because \Bbb R^{2\times2} because this set of matrices does not contain the zero matrix.

(e), however, is a subspace. Any linear combination of matrices in this set always yields a matrix with 0 in row 1, column 1 entry.

(f) is a subspace. A symmetric matrix is one of the form

\begin{bmatrix}a&b\\b&c\end{bmatrix}

Adding two symmetric matrices gives another symmetric matrix:

\begin{bmatrix}a_1&b_1\\b_1&c_1\end{bmatrix}+\begin{bmatrix}a_2&b_2\\b_2&c_2\end{bmatrix}=\begin{bmatrix}a_1+a_2&b_1+b_2\\b_1+b_2&c_1+c_2\end{bmatrix}

(g) is not a subspace. Consider the matrices

\begin{bmatrix}1&0\\0&0\end{bmatrix},\begin{bmatrix}0&0\\0&1\end{bmatrix}

Both matrices have determinant 0, but their sum is the identity matrix with determinant 1.

4 0
4 years ago
Drag the tiles to the correct boxes to complete the pairs.
worty [1.4K]

Answer:

i^223 = -i

i^113 = i

i^82 = -1

i^48 = 1

Step-by-step explanation:

These are rules of i.

i^1 = i

i^2 = -1

i^3 = -i

i^4 = 1

You just have to apply this to the powers you are given.

7 0
3 years ago
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