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Troyanec [42]
2 years ago
13

A full-grown giraffe is about 6 times heavier than a full-grown lion. A full-grown cheetah is about one-quarter as heavy as a fu

ll-grown lion. Together, they are about 450kg. What is the approximate mass of each animal?
Mathematics
2 answers:
Angelina_Jolie [31]2 years ago
3 0

Answer:

sorry i dont know

Step-by-step explanation:

nlexa [21]2 years ago
3 0

The mass of full grown giraffe is 372.42 kg and mass of full grown lion is 62.07 kg and mass of full grown cheetah is 15.51 kg

Solution:

Let "a" be the mass of full grown giraffe

Let "b" be the mass of full grown lion

Let "c" be the mass of full grown cheetah

A full-grown giraffe is about 6 times heavier than a full-grown lion

a = 6b ------- eqn 1

A full-grown cheetah is about one-quarter as heavy as a full-grown lion

\begin{gathered}c = \frac{1}{4} \times b\\\\c = \frac{b}{4} ----- eqn\ 2\end{gathered}

c=

4

1

×b

c=

4

b

−−−−−eqn 2

Together, they are about 450 kg

Therefore,

a + b + c = 450

Substitute eqn 1 and eqn 2 in above

\begin{gathered}6b + b + \frac{b}{4} = 450\\\\24b + 4b + b = 450 \times 4\\\\29b = 1800\\\\b = 62.07\end{gathered}

6b+b+

4

b

=450

24b+4b+b=450×4

29b=1800

b=62.07

Substitute b = 62.07 in eqn 1

\begin{gathered}a = 6(62.07)\\\\a = 372.42\end{gathered}

a=6(62.07)

a=372.42

Substitute b = 62.07 in eqn 2

c = \frac{62.07}{4} = 15.51c=

4

62.07

=15.51

Thus, mass of full grown giraffe is 372.42 kg and mass of full grown lion is 62.07 kg and mass of full grown cheetah is 15.51 kg

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Answers? with explanations
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Okay, so basically we have:
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One satellite is scheduled to be launched from Cape Canaveral in Florida, and another launching is scheduled for Vandenberg Air
Lisa [10]

Answer:

P(A) = 0.45

P(B) = 0.32

Step-by-step explanation:

Given

P(A) > P(B)

P(A\ u\ B) = 0.626

P(A\ n\ B) = 0.144

Required

Find P(A) and P(B)

We have that:

P(A\ u\ B) = P(A) + P(B) - P(A\ n\ B) --- (1)

and

P(A\ n\ B) = P(A) * P(B) --- (2)

The equations become:

P(A\ u\ B) = P(A) + P(B) - P(A\ n\ B) --- (1)

0.626 = P(A) + P(B) - 0.144

Collect like terms

P(A) + P(B) = 0.626 + 0.144

P(A) + P(B) = 0.770

Make P(A) the subject

P(A) = 0.770 - P(B)

P(A\ n\ B) = P(A) * P(B) --- (2)

0.144 = P(A) * P(B)

P(A) * P(B) = 0.144

Substitute: P(A) = 0.770 - P(B)

[0.770 - P(B)] * P(B) = 0.144

Open bracket

0.770P(B) - P(B)^2 = 0.144

Represent P(B) with x

0.770x - x^2 = 0.144

Rewrite as:

x^2 - 0.770x + 0.144 = 0

Expand

x^2 - 0.45x - 0.32x + 0.144 = 0

Factorize:

x[x - 0.45] - 0.32[x - 0.45]= 0

Factor out x - 0.45

[x - 0.32][x - 0.45]= 0

Split

x - 0.32= 0 \ or\ x - 0.45= 0

Solve for x

x = 0.32\ or\ x = 0.45

Recall that:

P(B) = x

So, we have:

P(B) = 0.32 \ or \ P(B) = 0.45

Recall that:

P(A) = 0.770 - P(B)

So, we have:

P(A) = 0.770 - 0.32 \ or\ P(A) =0.770 - 0.45

P(A) = 0.45 \ or\ P(A) =0.32

Since:

P(A) > P(B)

Then:

P(A) = 0.45

P(B) = 0.32

6 0
2 years ago
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