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3 years ago

What is the slope of a trend line that passes through the points (5, 80) and (7, 65)?

Mathematics

2 answers:

Leni [432]3 years ago

6 0

Answer:

-15/2

Just took the test.

Vlad [161]3 years ago

4 0

Answer:

-15/2 or -7.5 or -7½

Negative StartFraction 15 Over 2 EndFraction

Step-by-step explanation:

Slope or gradient of a line is the ratio of change in y co-ordinates to the change in x co-ordinates.

Therefore;

M=∆y÷∆x

The change in y co-ordinates is given by

∆y=y2-y1

Similarly, change in x co-ordinates is given by

∆x=x2-x1

Given the two points as (5, 80) and (7, 65)

X1=5 Y1=80

X2=7 Y2=65

∆y=65-80=-15

∆x=7-5=2

Hence ∆y÷∆x will be -15÷2=-7.5 or -7½

Negative StartFraction 15 Over 2 EndFraction

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lapo4ka [179]

Answer:

$S_{12}=\sum_{i=1}^{12} [\frac{3}{2}+(i-1)\times \frac{5}{6}]$

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Step-by-step explanation:

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$a_1=\frac{3}{2}+0\times \frac{5}{6}\\\\a_2=\frac{3}{2}+1\times \frac{5}{6}\\\\a_3=\frac{3}{2}+2\times \frac{5}{6}\\\\.\\.\\.\\a_n=\frac{3}{2}+(n-1)\times \frac{5}{6}\\\\S_n=a_1+a_2+a_3+......+a_n\\\\S_n=(\frac{3}{2}+0\times \frac{5}{6})+(\frac{3}{2}+1\times \frac{5}{6})+(\frac{3}{2}+2\times \frac{5}{6})+....+(\frac{3}{2}+[n-1]\times \frac{5}{6})\\\\S_n=\sum_{i=1}^n [\frac{3}{2}+(i-1)\times \frac{5}{6}]\\\\S_n=(\frac{3}{2}+\frac{3}{2}+\frac{3}{2}+...n\ times)+\frac{5}{6}(1+2+3+4+...+(n-1))\\\\$

$S_n=\frac{3}{2}\times n+\frac{5}{6}\times \frac{n(n-1)}{2}\\\\$

$S_{12}=\sum_{i=1}^{12} [\frac{3}{2}+(i-1)\times \frac{5}{6}]$

$S_{12}=\frac{3}{2}\times 12+\frac{5}{6}\times \frac{(12)(12-1)}{2}\\\\S_{12}=18+55\\\\S_{12}=73$

5 0

3 years ago

Alice's backyard is a rectangular piece of property that is twice as long as it is wide. The total area of her yard is 500 m^(2)

Alchen [17]

The approximate width of Alice's backyard is 22.36 in.

Let l be the length of the rectangle and w be the width.
l = 2w
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1000 m2 = 2w *w
500 m2 = w^2
√500 m2 = √w^2
w = <span>22.360679775 in or 22.36 in</span>

4 0

3 years ago

Read 2 more answers