<span>The input of days results in the output of total collected books. On day 1, 8 books were collected. Both inputs for days 2 and 3 have the same output of 13, meaning that no books were collected for day 3. After 5 days, 21 books were collected. The most books were collected on day 5.</span>
Answer:
18 credits if studying, if working this is usually monthly and does not reflect credit overload. Unless there are bank credit card payments to pay and normal charges.
Lets say charges are £20 a month and no student debt.
Plus 30 x monthly rent for annual proof for lettings. shows $30,000 credit worth + 15000 extra..
Average rent $1000 a month. = 12,000 45000-12000 = 33000 utility and necessary expenditure $3000 a year = $30,000.
Therefore debt can be considered long term payments at half this $15,000 p/y
or 7% of 45,000
7% = $3150 p/y / 12 = $262.5 p/m
with $11,850 of $30000 to be considered for credit worth + approval and interest in any 12 month term.
Should Terrance require low interest credit his worth thereafter if rent was low at $1000 a month, he would be considered for maximum $880 repayment terms for short term new loans.
Step-by-step explanation:
Answer:
10,485,760
Step-by-step explanation:
Multiply -4
A) zeroes
P(n) = -250 n^2 + 2500n - 5250
Extract common factor:
P(n)= -250 (n^2 - 10n + 21)
Factor (find two numbers that sum -10 and its product is 21)
P(n) = -250(n - 3)(n - 7)
Zeroes ==> n - 3 = 0 or n -7 = 0
Then n = 3 and n = 7 are the zeros.
They rerpesent that if the promoter sells tickets at 3 or 7 dollars the profit is zero.
B) Maximum profit
Completion of squares
n^2 - 10n + 21 = n^2 - 10n + 25 - 4 = (n^2 - 10n+ 25) - 4 = (n - 5)^2 - 4
P(n) = - 250[(n-5)^2 -4] = -250(n-5)^2 + 1000
Maximum ==> - 250 (n - 5)^2 = 0 ==> n = 5 and P(5) = 1000
Maximum profit =1000 at n = 5
C) Axis of symmetry
Vertex = (h,k) when the equation is in the form A(n-h)^2 + k
Comparing A(n-h)^2 + k with - 250(n - 5)^2 + 1000
Vertex = (5, 1000) and the symmetry axis is n = 5.
