Answer:
n = 59
Step-by-step explanation:
I find it easiest to work problems of this kind using a graphing calculator. That way, extraneous solutions can be avoided. It seems to work well to rewrite the problem, so you're looking for a value of n that makes the result zero. Here, that would mean you want ...
... f(n) = √(n+5) -√(n-10) -1
_____
The solution by hand involves eliminating the root symbols. You do that by squaring the equation:
... n +5 -2√((n+5)(n-10)) + n -10 = 1
Now, we isolate the remaining root and square again.
... 2n -6 = 2√((n+5)(n-10)) . . . collect terms, add 2√( ) -1
... n -3 = √(n²-5n-50) . . . . . . . divide by 2
... n² -6n +9 = n² -5n -50 . . . . square both sides
... 59 = n . . . . . . . . . . . . . . . . . add 50 +6n -n²
Answer: Endpoint = (-4,6)
Step-by-step explanation:
To find any endpoint use the formula

multiply each by 2 to simplify
take the equations and simplify
6+
= 2 -2+
= 4 =
-6 -6 +2 +2
= -4
= 6
To check use the Midpoint formula

Helen = 30 T (T = tickets)
Gina = 30 + 20 = 50 T
20% of 50 = 10
30 + 10 = 404
50 - 10 = 40
Gina must give 20% of her tickets for them to have equal amount of tickets.
Hope this helps!!
The discriminante :
b^2-4ac
1^2 - 4 * -2 * -28 = 1 - 224 = -223
When the discriminant (b^2-4ac) is less than 0, the equation had no real solutions.
-223<0, so, 2x^2+x-28 = 0 has no real solutions.
Hope that helps :)