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guapka [62]
3 years ago
11

You are choosing between two different cell phone plans. The first plan charges a rate of 24 cents per minute. The second plan c

harges a monthly fee of $39.95 plus 10 cents per minute. How many minutes would you have to use in a month in order for the second plan to be preferable?
Mathematics
2 answers:
Virty [35]3 years ago
7 0

Answer: 286 minutes

Step-by-step explanation:

x : # of months that has gone by

0.24x : cost of the 24 cent plan after "x" minutes

39.95 + 0.10x : cost of the 10 cent plan after "x" minutes

1. 39.95 + 0.10x > 0.24x

2. 39.95 > 0.24x - 0.10x

3. 39.95 > 0.14x

4. 285.36 > x

x must be AT LEAST 286 minutes for plan #2 (39.95 + 0.10x) to be a better deal

natima [27]3 years ago
4 0

Answer:

286 minutes.

Step-by-step explanation:

Plan one: .24x

Plan two: 39.95 + .10x

When x = 286, the price of plan one is $68.64, which is higher than plan two which is $68.55. This makes the second plan preferable after 286 minutes of use.

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A statistician calculates that 8% of Americans own a Rolls Royce. If the statistician is right, what is the probability that the
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Answer:

0.007 = 0.7% probability that the proportion of Rolls Royce owners in a sample of 595 Americans would differ from the population proportion by more than 3%

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

A statistician calculates that 8% of Americans own a Rolls Royce.

This means that p = 0.08

Sample of 595:

This means that n = 595

Mean and standard deviation:

\mu = p = 0.08

s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.08*0.92}{595}} = 0.0111

What is the probability that the proportion of Rolls Royce owners in a sample of 595 Americans would differ from the population proportion by more than 3%?

Proportion above 8% + 3% = 11% or below 8% - 3% = 5%. Since the normal distribution is symmetric, these probabilities are equal, and so we find one of them and multiply by 2.

Probability the proportion is less than 5%:

P-value of Z when X = 0.05. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0.05 - 0.08}{0.0111}

Z = -2.7

Z = -2.7 has a p-value of 0.0035

2*0.0035 = 0.0070

0.007 = 0.7% probability that the proportion of Rolls Royce owners in a sample of 595 Americans would differ from the population proportion by more than 3%

8 0
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