Which is equivalent to cos^-1(0) answer in radian

Mathematics

1 answer:

ruslelena [56]3 years ago

8 0

Answer:

Step-by-step explanation:

cos ^-1(0)=(2n+1) π/2

where n is an integer.

if 0 ≤α ≤2 π

n=0,1

cos ^-1(0)=π/2,3π/2

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Answer:

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Step-by-step explanation:

Step 1:

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Complete the statements about the key features of the graph of f(x) = x5 – 9x3. As x goes to negative infinity, f(x) goes to neg

Mars2501 [29]

The function is $f(x)= x^{5} -9x ^{3}$

1. let's factorize the expression $x^{5} -9x ^{3}$ :

$f(x)= x^{5} -9x ^{3}= x^{3} ( x^{2} -9)=x^{3}(x-3)(x+3)$

the zeros of f(x) are the values of x which make f(x) = 0.

from the factorized form of the function, we see that the roots are:

-3, multiplicity 1
3, multiplicity 1
0, multiplicity 3

(the multiplicity of the roots is the power of each factor of f(x) )

2.
The end behavior of f(x), whose term of largest degree is $x^{5}$ , is the same as the end behavior of $x^{3}$ , which has a well known graph. Check the picture attached.

(similarly the end behavior of an even degree polynomial, could be compared to the end behavior of $x^{2}$ )

so, like the graph of $x^{3}$ , the graph of $f(x)= x^{5} -9x ^{3}$ :

"As x goes to negative infinity, f(x) goes to negative infinity, and as x goes to positive infinity, f(x) goes to positive infinity. "