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Aleksandr [31]
3 years ago
10

Which is equivalent to cos^-1(0) answer in radian

Mathematics
1 answer:
ruslelena [56]3 years ago
8 0

Answer:

Step-by-step explanation:

cos ^-1(0)=(2n+1) π/2

where n is an integer.

if 0 ≤α ≤2 π

n=0,1

cos ^-1(0)=π/2,3π/2

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Can I have help with the question
sleet_krkn [62]

Answer:

Midpoint = (3.5, 4.5)

Perpendicular bisector = y =  \frac{7}{9} x + \frac{16}{9}

Step-by-step explanation:

[] We can solve this using the midpoint formula:

-> See attached

[] Plug-in our coordinates and solve:

(\frac{7+0}{2} ,\frac{0+9}{2} )=(\frac{7}{2} ,\frac{9}{2} )=(3.5,4.5 )

[] Now we will find the slope to solve for the perpendicular bisector.

-> We will use slope-intercept form, see attached

\frac{9-0}{0-7}=\frac{9}{-7}

-> The slopes of two perpendicular lines are negative reciprocals of each other, so \frac{7}{9} will be the slope of or perpendicular bisector

-> Now we can solve for the equation by using y – y1 = m ( x – x1), were y1 and x1 are the coordinates of our midpoint

y - 4.5 = \frac{7}{9} (x-3.5)

y - 4.5 = \frac{7}{9} x-\frac{49}{18}

y = \frac{7}{9} x-\frac{49}{18} + 4.5

y =  \frac{7}{9} x + \frac{16}{9}

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

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