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3 years ago

Drag each number to the correct location on the table. Each number can be used more than once, but not all numbers will be used.

Mathematics

1 answer:

muminat3 years ago

8 0

Answer:

1. $12x^2-13.4x-11$

- Degree: 2

- Number of terms: 3

2. $7x^3+168$

- Degree: 3

- Number of terms: 2

3. $9x^4-9$

- Degree: 4

- Number of terms: 2

Step-by-step explanation:

For this exercise you need to remember the multiplication of signs:

$(+)(+)=+\\(-)(-)=+\\(-)(+)=-\\(+)(-)=-$

1. Given:

$(4x + 2.2)(3x - 5)$

Apply the Distributive property:

$=12x^2+6.6x-20x-11$

Add the like terms:

$=12x^2-13.4x-11$

You can idenfity that:

- Degree: 2

- Number of terms: 3

2. Given:

$(-304 +503 - 12) + (7x^3 - 25 + 6)$

Add the like terms:

$=187 + 7x^3 - 25 + 6=7x^3+168$

You can idenfity that:

- Degree: 3

- Number of terms: 2

3. Given:

$(3x^2 - 3)(3x^2 + 3)$

Apply Distributive property:

$=9x^4-9x^2+9x^2-9$

Add the like terms:

$=9x^4-9$

You can idenfity that:

- Degree: 4

- Number of terms: 2

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Tony has a hosepipe. The length of the hosepipe is 20 m. Tony stores the hosepipe on a reel. The weight of the reel is 1.4 kg. 1

harina [27]

Answer:

the total weight of the hosepipe and the reel is 7.4 kg

Step-by-step explanation:

First, we need to find the weight of the hosepipe, we know that 1/2 metre of the hosepipe has a weight of 150 grams, therefore we can conclude that 1 meter has a weight of (150)(2) = 300 grams.

If one meter weighs 300 grams, then 20 meters have a weight of $20(300) = 6000$ grams. But since 1000 grams are 1 kg, this would be equivalent to 6 kg.

Now, to find the total weight of the hosepipe and the reel we are going to sum up the 2 weights:

Total weight = hose pipe weight + reel weight

Total weight = 6 kg + 1.4 kg

Total weight = 7.4 kg.

Therefore, the total weight of the hosepipe and the reel is 7.4 kg

8 0

3 years ago

Which recursive sequence would produce the sequence 8,-35,137,…?

vagabundo [1.1K]

The recursive sequence that would produce the sequence 8,-35,137,… is T(n + 1) = -3 - 4T(n) where T(1) = 8

<h3>How to determine the recursive sequence that would produce the sequence?</h3>

The sequence is given as:

8,-35,137,…

From the above sequence, we can see that:

The next term is the product of the current term and -4 added to -3

i.e.

Next term = -3 + Current term * -4

So, we have:

T(n + 1) = -3 + T(n) * -4

Rewrite as:

T(n + 1) = -3 - 4T(n)

Hence, the recursive sequence that would produce the sequence 8,-35,137,… is T(n + 1) = -3 - 4T(n) where T(1) = 8

Read more about recursive sequence at

brainly.com/question/1275192

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4 0

1 year ago

Help please I need help :(

maks197457 [2]

A = 1 and 8

B = 2 and 4

C = 2 and 7

I’m pretty sure this is right? I’m still learning too :p

5 0

3 years ago

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What is the same as moving the decimal point 3 places to the right in a decimal point.

ladessa [460]

Answer:

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Let X1 and X2 be independent random variables with mean μand variance σ².

My name is Ann [436]

Answer:

a) $E(\hat \theta_1) =\frac{1}{2} [E(X_1) +E(X_2)]= \frac{1}{2} [\mu + \mu] = \mu$

So then we conclude that $\hat \theta_1$ is an unbiased estimator of $\mu$

$E(\hat \theta_2) =\frac{1}{4} [E(X_1) +3E(X_2)]= \frac{1}{4} [\mu + 3\mu] = \mu$

So then we conclude that $\hat \theta_2$ is an unbiased estimator of $\mu$

b) $Var(\hat \theta_1) =\frac{1}{4} [\sigma^2 + \sigma^2 ] =\frac{\sigma^2}{2}$

$Var(\hat \theta_2) =\frac{1}{16} [\sigma^2 + 9\sigma^2 ] =\frac{5\sigma^2}{8}$

Step-by-step explanation:

For this case we know that we have two random variables:

$X_1 , X_2$ both with mean $\mu = \mu$ and variance $\sigma^2$

And we define the following estimators:

$\hat \theta_1 = \frac{X_1 + X_2}{2}$

$\hat \theta_2 = \frac{X_1 + 3X_2}{4}$

Part a

In order to see if both estimators are unbiased we need to proof if the expected value of the estimators are equal to the real value of the parameter:

$E(\hat \theta_i) = \mu , i = 1,2$