Answer:
y-3
Problem:
What is the remainder when the dividend is xy-3, the divisor is y, and the quotient is x-1. ?
Step-by-step explanation:
Dividend=quotient×divisor+remainder
So we have
xy-3=(x-1)×(y)+remainder
xy-3=(xy-y)+remainder *distributive property
Now we just need to figure out what polynomial goes in for the remainder so this will be a true identity.
We need to get rid of minus y so we need plus y in the remainder.
We also need minus 3 in the remainder.
So the remainder is y-3.
Let's try it out:
xy-3=(xy-y)+remainder
xy-3=(xy-y)+(y-3)
xy-3=xy-3 is what we wanted so we are done here.
Answer:
The answer to your question is (4, 6)
Step-by-step explanation:
Data
E ( 9 , 7 )
F ( - 1, 5)
Formula


Substitution and simplification


Xm = 4


Ym = 6
Result
(4 , 6)
Answer: x = 18
Step-by-step explanation:
Answer:

Step-by-step explanation:
Let me know if that is not the same equation you wrote and if you have any questions !!