Answer:
here i finished!
hope it helps yw!
Step-by-step explanation:
The doubling period of a bacterial population is 15 minutes.
At time t = 90 minutes, the bacterial population was 50000.
Round your answers to at least 1 decimal place.
:
We can use the formula:
A = Ao*2^(t/d); where:
A = amt after t time
Ao = initial amt (t=0)
t = time period in question
d = doubling time of substance
In our problem
d = 15 min
t = 90 min
A = 50000
What was the initial population at time t = 0
Ao * 2^(90/15) = 50000
Ao * 2^6 = 50000
We know 2^6 = 64
64(Ao) = 50000
Ao = 50000/64
Ao = 781.25 is the initial population
:
Find the size of the bacterial population after 4 hours
Change 4 hr to 240 min
A = 781.25 * 2^(240/15
A = 781.25 * 2^16
A= 781.25 * 65536
A = 51,199,218.75 after 4 hrs
Answer:
Ea and St
Step-by-step explanation:
Answer:5 7/18
Step-by-step explanation:
7 2/9 - 1 5/6
65/9-1 5/6
65/9-11/6
97/18
5 7/18
Answer:
The solution is:
Step-by-step explanation:
Given the expression
Solving
so
∵ 
Therefore, the solution is:
<span>x = child ticket price
y = adult ticket price
5x+3y=52 the cost accounting for the first group.
3x+2y=38 the cost accounting for the second group.
Child price: 5$
Adult price: 9$</span>
