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yawa3891 [41]
3 years ago
6

Simplify. 4/x^2-35 - 1/x+5

Mathematics
1 answer:
Oksana_A [137]3 years ago
6 0
If I understand your question well, I suppose you mean \frac{4}{ x^{2} -35} -  \frac{1}{x+5}
\frac{4}{ x^{2} -35} - \frac{1}{x+5} =  \frac{4}{(x+5)(x-7)}- \frac{1}{x+5} \\ = \frac{1}{x+5}( \frac{4}{x-7}-1) \\ = \frac{1}{x+5}( \frac{4}{x-7}- \frac{x-7}{x-7}) \\ = \frac{1}{x+5}( \frac{4-x+7}{x-7}) \\ = \frac{1}{x+5}( \frac{11-x}{x-7}) \\ = \frac{11-x}{ x^{2} -35}
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The formula for the volume of w sphere is v=4\3 r3 what is the formula solved for r?
Lyrx [107]
V of w sphere = \frac{4}{3}\pir³
Multiply by 3 on either sides to get rid of the fraction.
V * 3 =  \frac{4}{3} *3 \pi r^3
3V = 4\pir³
Now divide either sides by 4\pi to isolate r³
\frac{3V}{4 \pi } =  \frac{4 \pi }{4 \pi }r³
4\pi and 4\pi cancels out
\frac{3V}{4 \pi } = r³
Take the cube root to isolate r.
\sqrt[3]{ \frac{3V}{4 \pi } } =  \sqrt[3]{r^3}
the cube root cancels the cube

\sqrt[3]{ \frac{3V}{4 \pi } } = r
6 0
3 years ago
C ÷ -3 = 8 I’ve been stuck on this prob for awhile and I need help on it
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8 0
3 years ago
joe has a piggy bank with $8.90 split upon nickels, dimes, and quarters. The piggy bank contains 76 coins in all. The number of
kozerog [31]

Answer:

There are 38 dimes, 22 nickels and 16 quarters.

Step-by-step explanation:

Let n, d and q represent the # of nickels, dimes and quarters respectively.

Then n + d + q = 76

The value of a nickel is $0.05; that of a dime is $0.10, and that of a quarter is $0.25.

Thus, the value of n nickels is $0.05n (and so on).

The total value of the coins is $0.05n + $0.10d + $0.25q = $8.90.

d = n + q allows us to eliminate d.

First, n + d + q = 76 becomes n + (n + q) + q = 76, and second:

$0.05n + $0.10(n + q) + $0.25q = $8.90.  Here we have succeeded in eliminating d from two different equations, and now we have these two different equations in two unknowns (n and q), which is solvable.

Simplifying both equations, we get:

2n + 2q = 76 and

5n + 10n + 10q + 25q = 890, or 15n + 35q = 890

Let's use the substitution method of solving linear equations:

Rewrite 2n  + 2q = 76 as n + q = 38, or n = 38 - q.  Substituting this result into the second equation, we get:

15(38 - q) + 35 q = 890, or

  570 - 15q + 35q = 890, or

   570 + 20 q = 890.  Then 20q = 890 - 570 = 320, and q = 320/20 = 16.

There are 16 quarters.  Thus, the number of nickels is n = 38 - 16 = 22.

Finally, since n + d + q = 76, 22 + d + 16 = 76, or:

22 + d = 60, or d = 60 - 22 = 38.

There are 38 dimes, 22 nickels and 16 quarters.

4 0
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Answer:

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Step-by-step explanation:

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3 years ago
Calculate for log 4 4^8
jek_recluse [69]
So log4 (4^8) is just 8
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