Ask question

Ask question

All categories

3 years ago

6

Simplify. 4/x^2-35 - 1/x+5

1 answer:

Oksana_A [137]3 years ago

6 0

If I understand your question well, I suppose you mean $\frac{4}{ x^{2} -35} - \frac{1}{x+5}$
$\frac{4}{ x^{2} -35} - \frac{1}{x+5} = \frac{4}{(x+5)(x-7)}- \frac{1}{x+5} \\ = \frac{1}{x+5}( \frac{4}{x-7}-1) \\ = \frac{1}{x+5}( \frac{4}{x-7}- \frac{x-7}{x-7}) \\ = \frac{1}{x+5}( \frac{4-x+7}{x-7}) \\ = \frac{1}{x+5}( \frac{11-x}{x-7}) \\ = \frac{11-x}{ x^{2} -35}$

You might be interested in

A gerbil cage,priced at $18, is discounted 20% for one week, and then this price is marked up 20%. is the price back to 20% expl

stiks02 [169]

No, it isn't!

first, the discount is 20 percent of 18 dollars, that is 18/5=3.6

this means that during the first week the prize is 18-3.6=14.4

now, the prize is marked up 20 % of 14.4! this is 2.88

so the prize later will be 14.4+2.88, that is 17.28, not 18

what is relevant here is what a number is a percent OF

6 0

3 years ago

Can you help me please?

iren [92.7K]

Finding the volume of a cube involves multiplying with this formula.

Height * Width * Length = volume

To find what the side lengths are, we can take the cube root of 64.

∛64 = 4

Height = 4

Width = 4

Length = 4

These sides are multiplied together to get 64.

The only answer choice that makes sense is Option A.

______

Best Regards,

Wolfyy :)

6 0

3 years ago

Read 2 more answers

Use Hooke's Law to determine the work done by the variable force in the spring problem. A force of 450 newtons stretches a sprin

vlada-n [284]

Answer:

The work done is 202.50Nm

Step-by-step explanation:

Given

$F =450N$

$x_1 = 30cm$

$x_2 = 60cm$

Required

The work done

First, we calculate the spring constant (k)

$F = kx_1$

$450N = k *30cm$

$k = \frac{450N}{30cm}$

$k =15N/cm$

So:

$F = kx_1$

$F(x) = 15x$

The work done using Hooke's law is:

$W =\int\limits^a_b {F(x)} \, dx$

This gives:

$W =\int\limits^{60}_{30} {15x} \, dx$

Rewrite as:

$W =15\int\limits^{60}_{30} {x} \, dx$

Integrate

$W =15 \frac{x^2}{2}|\limits^{60}_{30}$

This gives:

$W =15 *\frac{60^2 - 30^2}{2}$

$W =15 *\frac{2700}{2}$

$W =15 *1350$

$W =20250N-cm$

Convert to Nm

$W =\frac{20250Nm}{100}$

$W =202.50Nm$

7 0

3 years ago

Which expression gives the prime<br> factorization of 80?<br> I need help please..

Alja [10]

The correct answer is actually choice D.

8 0

3 years ago

Line A has an equation of y=-2/5x + 3. What is the slope of a line perpendicular

Nat2105 [25]

Answer:

$\frac{5}{2}$

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - $\frac{2}{5}$ x + 3 ← is in slope- intercept form

with slope m = - $\frac{2}{5}$

Given a line with slope m then the slope of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$ = - $\frac{1}{-\frac{2}{5} }$ = $\frac{5}{2}$

5 0

3 years ago