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yawa3891 [41]
3 years ago
6

Simplify. 4/x^2-35 - 1/x+5

Mathematics
1 answer:
Oksana_A [137]3 years ago
6 0
If I understand your question well, I suppose you mean \frac{4}{ x^{2} -35} -  \frac{1}{x+5}
\frac{4}{ x^{2} -35} - \frac{1}{x+5} =  \frac{4}{(x+5)(x-7)}- \frac{1}{x+5} \\ = \frac{1}{x+5}( \frac{4}{x-7}-1) \\ = \frac{1}{x+5}( \frac{4}{x-7}- \frac{x-7}{x-7}) \\ = \frac{1}{x+5}( \frac{4-x+7}{x-7}) \\ = \frac{1}{x+5}( \frac{11-x}{x-7}) \\ = \frac{11-x}{ x^{2} -35}
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6 0
3 years ago
Can you help me please?
iren [92.7K]

Finding the volume of a cube involves multiplying with this formula.

Height * Width * Length = volume

To find what the side lengths are, we can take the cube root of 64.

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3 years ago
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vlada-n [284]

Answer:

The work done is 202.50Nm

Step-by-step explanation:

Given

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Required

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F = kx_1

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The work done using Hooke's law is:

W =\int\limits^a_b {F(x)} \, dx

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Rewrite as:

W =15\int\limits^{60}_{30} {x} \, dx

Integrate

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This gives:

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3 years ago
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Nat2105 [25]

Answer:

\frac{5}{2}

Step-by-step explanation:

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5 0
3 years ago
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