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2 years ago

What is the answer and show your work plz

Mathematics

1 answer:

alexandr402 [8]2 years ago

8 0

Answer:

C. Multiply both 2and 4 into it then you'll have the answer

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Please help.

yan [13]

131 3/4 ⇒ 115 5/8 ⇒ 5 2/3

Subtract 131 3/4 by 115 5/8.

131 3/4 ⇒ 131 6/8
131 6/8 - 115 5/8 = 16 1/8

Now add 16 1/8 + 5 2/3 and this will give you how much weight she lost in all.

16 1/8 ⇒ 16 3/24
5 2/3 ⇒ 5 16/24
16 3/24 + 5 16/24 = 21 19/24

Felice lost 21 19/24 pounds in all.

4 0

2 years ago

Read 2 more answers

Combine the rational expressions into a single fraction and reduce it in the lowest terms.

Lostsunrise [7]

Answer:

13. -3 14. (x+1)(2x-7) / (x-6)(x+3)

Step-by-step explanation:

5 0

3 years ago

Moby sold half his toy car collection, and then bought 12 more cars the next day. He now has 48 toy cars. How many cars did he h

castortr0y [4]

Answer: 72 cars.

Step-by-step explanation:

Let be "x" the number of toys that Moby had to start with.

According to the information given in the exercise, Moby sold half his toy car collection. This can be represented with the following expression:

$\frac{1}{2}x$

Then he bought 12 more cars, giving a total amount of 48 toy cars.

Therefore, the equation that represents this situation is the equation shown below:

$x-\frac{1}{2}x+12=48$

Now you must solve for "x" in order to find its value.

You get that this is:

$\frac{1}{2}x+12=48\\\\\frac{1}{2}x=48-12\\\\\frac{1}{2}x=36\\\\x=(36)(2)\\\\x=72$

7 0

3 years ago

I need help ASAP. Will give Brainliest.

Volgvan

Answer:

4,5

Step-by-step explanation:

Your welcome! :)

Good Luck!

8 0

3 years ago

Read 2 more answers

The volume V of an ice cream cone is given by V = 2 3 πR3 + 1 3 πR2h where R is the common radius of the spherical cap and the c

Nuetrik [128]

Answer:

The change in volume is estimated to be 17.20 $\rm{in^3}$

Step-by-step explanation:

The linearization or linear approximation of a function $f(x)$ is given by:

$f(x_0+dx) \approx f(x_0) + df(x)|_{x_0}$ where $df$ is the total differential of the function evaluated in the given point.

For the given function, the linearization is:

$V(R_0+dR, h_0+dh) = V(R_0, h_0) + \frac{\partial V(R_0, h_0)}{\partial R}dR + \frac{\partial V(R_0, h_0)}{\partial h}dh$

Taking $R_0=1.5$ inches and $h=3$ inches and evaluating the partial derivatives we obtain:

$V(R_0+dR, h_0+dh) = V(R_0, h_0) + \frac{\partial V(R_0, h_0)}{\partial R}dR + \frac{\partial V(R_0, h_0)}{\partial h}dh\\V(R, h) = V(R_0, h_0) + (\frac{2 h \pi r}{3} + 2 \pi r^2)dR + (\frac{\pi r^2}{3} )dh$

substituting the values and taking $dx=0.1$ and $dh=0.3$ inches we have:

$V(R_0+dR, h_0+dh) =V(R_0, h_0) + (\frac{2 h \pi r}{3} + 2 \pi r^2)dR + (\frac{\pi r^2}{3} )dh\\V(1.5+0.1, 3+0.3) =V(1.5, 3) + (\frac{2 \cdot 3 \pi \cdot 1.5}{3} + 2 \pi 1.5^2)\cdot 0.1 + (\frac{\pi 1.5^2}{3} )\cdot 0.3\\V(1.5+0.1, 3+0.3) = 17.2002\\\boxed{V(1.5+0.1, 3+0.3) \approx 17.20}$

Therefore the change in volume is estimated to be 17.20 $\rm{in^3}$

4 0

2 years ago