Answer:
a. P(x = 0 | λ = 1.2) = 0.301
b. P(x ≥ 8 | λ = 1.2) = 0.000
c. P(x > 5 | λ = 1.2) = 0.002
Step-by-step explanation:
If the number of defects per carton is Poisson distributed, with parameter 1.2 pens/carton, we can model the probability of k defects as:

a. What is the probability of selecting a carton and finding no defective pens?
This happens for k=0, so the probability is:

b. What is the probability of finding eight or more defective pens in a carton?
This can be calculated as one minus the probablity of having 7 or less defective pens.



c. Suppose a purchaser of these pens will quit buying from the company if a carton contains more than five defective pens. What is the probability that a carton contains more than five defective pens?
We can calculate this as we did the previous question, but for k=5.

Answer: =4.4n-13
Step-by-step explanation:
Let's simplify step-by-step.
2n−9−(−2.4n+4)
Distribute the Negative Sign:
=2n−9+−1(−2.4n+4)
=2n+−9+−1(−2.4n)+(−1)(4)
=2n+−9+2.4n+−4
Combine Like Terms:
=2n+−9+2.4n+−4
=(2n+2.4n)+(−9+−4)
=4.4n+−13
It is less than 324.21, because as you can see, all the numbers are equal until you get to the 0 & 1, and 1 is greater than 0
Mean=8.1 (add all numbers and divide by how many there r)
Median=9.25 (place all numbers in a chronological line and find the middle value)
Mode=9.2 (value that appears the most)
Range=10.5 (10.5-0)