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3 years ago

What's the proper name of this quadrilateral

Mathematics

2 answers:

mamaluj [8]3 years ago

8 0

C. Trapezoid is the correct term for that figure.

Yuliya22 [10]3 years ago

6 0

A Trapezoid has one pair of parallel sides. So your answer would be Trapezoid

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A large container of yogurt contains 36 ounces. How many cups of yogurt does the container hold?

iris [78.8K]

Answer:

The container holds 4.5 cups of yogurt

Step-by-step explanation:

Here, given the number of ounces of yogurt in a container, we want to calculate the number of cups the container can hold

Mathematically, we need a conversion factor

1 cup contains 8 ounces

but here

x cups contains 36 ounces

8 * x= 36 * 1

8x = 36

x = 36/8

x = 4.5

6 0

3 years ago

4x-6y=-24 2x-3y=-6 graphed

sergeinik [125]

Answer:

Step-by-step explanation:

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3 years ago

I have to find those triangles similar or not. but I don't know where to start.

love history [14]

We begin by rearranging the triangles.

In the first triangle:

x+66+90=180

x+156=180

x=180-156

x=24

In the second triangle

y+90+24=180

y+114=180

y=180-114

y=66

Note: Similar triangles are the same shape, but not necessarily the same size.

We see that the angles in both triangles are exactly the same.

We conclude that the triangles are similar.

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1 year ago

A total of 30 players will play basketball at a park. There will be exactly 5 players on each team . Which statement correctly e

Delvig [45]

You first want to make an equation for the problem. Let x be the number of teams needed since the problem doesn’t include it.
30=5x
Divide 5 by both sides to get x on its own side
*What you do to one side you do to the other
30/5=5x/5
6=x

8 0

3 years ago

Read 2 more answers

A large box contains 10,000 ball bearings. A random sample of 120 is chosen. The sample mean diameter is 10 mm, and the standard

ser-zykov [4K]

Answer:

Option a) A 95% confidence interval for the mean diameter of the 120 bearings in the sample is $10 \pm 1.96\displaystyle\frac{0.24}{\sqrt{120}}$ .

Step-by-step explanation:

We are given the following information in the question:

Sample size, n = 120

Sample mean = 10 mm

Standard Deviation = 0.24 mm

Formula:

$\mu \pm z_{critical}\frac{\sigma}{\sqrt{n}}$

$z_{critical}\text{ at}~\alpha_{0.05} = 1.96$

$10 \pm 1.96\displaystyle\frac{0.24}{\sqrt{120}}$

Hence, the correct interpretation for the confidence interval is given by option a).

A 95% confidence interval for the mean diameter of the 120 bearings in the sample is $10 \pm 1.96\displaystyle\frac{0.24}{\sqrt{120}}$ .

We have to consider the factor of sampling of 120 ball bearings from a population of 10,000 ball bearings.

8 0

3 years ago