Answer:
31 bits.
Explanation:
Given, total number of registers = 55
Total instructions = 60
Size of memory = 16 KB
Now, no of registers are 55. We find the next greater or equal power of 2 which is 64 = 26. Hence, 6 bits are required to represent a register operand.
Number of instructions = 60. We find the next greater or equal power of 2 which is 64 = 26. Hence, 6 bits are required to represent a instruction.
Size of memory = 64 KB = 26 * 210 * 23 bits = 219 bits. Hence, 19 bits are required to represent a memory location.
Now, an instruction has 2 parts, opcode and operand. As given there are only two address instructions which are memory operand and register operand.
Hence, total bits would be: 6 bits (opcode) + 6 bits (register operand) + 19 (memory operand) = 31 bits.
Answer:
It leaves behind Error Code 5
Explanation:
This happens when the parameter provided fails the function requirement this could be as a result of wrong data type or when the parameter provided exceeds the function requirement.
Answer:kalo gk salah yang
a
Explanation:
Answer:
B) the time it takes for the required sector to position itself under the read/write head.
Explanation:
In Computer science, Access time is the time it takes for the required sector to position itself under the read/write head. It is usually measured in milliseconds.
It is the speed of the storage device.
