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S_A_V [24]
3 years ago
5

Help me I don't understand this lesson

Mathematics
2 answers:
Leni [432]3 years ago
7 0
The answer is d = 1.2t
VashaNatasha [74]3 years ago
6 0
The answer is d=0.6t , look at the graph and you should see why.
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6) A coat at Target is marked down 22% from its original
Aloiza [94]

Answer:

$140.90

Step-by-step explanation:

**22% = 0.22**

X = 109.90 / (1 - 0.22)

X = 109.90 / 0.78

X = 140.90

6 0
3 years ago
Given ABCDEF ≅ GHIJKL .
Karolina [17]
If they are congruent, then angle K = angle E which is 114
8 0
4 years ago
Read 2 more answers
Here are five digits 0,1,4,5,8 use all five digits to to make this correct _ _ x 2 = _ _
lesya [120]
Here are five digits 0,1,4,5,8 use all five digits to to make this correct _ _ x 2 = _ _
54x2=108
8 0
4 years ago
Can you help and when you answer please put down the letter of the question you are answering
Bezzdna [24]

Answer:

a. 10 5/8

b. 1 4/9

c. 5 7/12

d. 17 5/6

e. 5 1/10

f. 4 7/8

g. 133 3/8

h. 24 11/12

i. 19 7/10

j. 11 5/12

k. 1 5/12

l. 13 7/9

Step-by-step explanation:

Hello! The step by step solution is to simply add them together. Let's take a. 7 3/8 + 3 1/4 for an example. Change the denominator (the bottom number of the fraction) into something both can go into. 4 can go into 8 and 8 can go into 8. Rewrite the fractions beside the actual numbers. Example: /8 and /8 then remember, 4 goes into 8 two times. So do 1x2=2. Then remember 8 goes into 8 1 time so do 3x1=3. Add the two fractions 3/8+2/8= 5/8. Then add the whole numbers as well. 7+3+5/8= 10 5/8. I know that it's really confusing explaining it through words but if you ever need further explanation don't hesitate to ask! :)

7 0
3 years ago
Find x when : 3x^3 - 2x +1 = 0
notsponge [240]
Answer:  x = "-1 " ;  <u>and</u>:  "(1 ± √3) / 2" .
____________________________________________
Explanation:
____________________________________________
Given:  3x³ −  2x  + 1 = 0 ;  Find "x" ; 

Factor:  "3x³ −  2x + 1"  ;

3x³ − 2x + 1 = (3x² <span>− 3x + 1)(x + 1) ;

Now, set the equation equal to "0" (zero);

</span> (3x² − 3x + 1)(x + 1) = 0 ;

x = 0  ; when:
__________________________________
(x + 1) = 0 ;  and/or: when:

(3x² − 3x + 1) = 0 ;
__________________________________

Start with "x + 1 = 0" ;

Subtract "1" from each side of the equation ; to isolate "x" on one side of the <span>equation ; and</span> to solve for "x" ; 

              x + 1 − 1 = 0 − 1 ; 

                x = -1 ;

_______________________________
Now, try:  

3x² − 3x + 1 = 0 ;

Since:  "3x² − 3x + 1 " cannot be factored; and since:

  "3x² − 3x + 1 = 0" ; is written in the "quadratic equation format"; that is:

  "ax² + bx + c = 0 ;  a ≠ 0;  We can use the "quadratic equation formula" to solve for "x" ;  

in which "a = 3" ;   
              "b = -3" ;
              "c = 1" ;
     
The quadratic equation formula is:
__________________________________

x = [-b ± √(b²−4ac] / 2a ;

   = ?  (Let us plug in our known values for "a, b, & c"l 

x = { [-(-3] ± [√[(-3²) − (4*3*1)] } / {2* 3} ;

x = [3 ± √(9 − 12)] / 6 

x = [3 ± √(-3 )] / 6 ; 

x = (1 ± √3) / 2 .
<span>__________________________________________________
So, the answers are:  x = " -1 " ;  and:  "</span>(1 ± √3) / 2 " .
__________________________________________________
8 0
3 years ago
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