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Y_Kistochka [10]
3 years ago
11

Here are five digits 0,1,4,5,8 use all five digits to to make this correct _ _ x 2 = _ _

Mathematics
1 answer:
lesya [120]3 years ago
8 0
Here are five digits 0,1,4,5,8 use all five digits to to make this correct _ _ x 2 = _ _
54x2=108
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what is a survey question with the following information: in one school there are 6 sets of twins 2 sets of triplets and one set
Taya2010 [7]
Whats the question? You have no questin XD

3 0
3 years ago
Drew wrote a four digit number less than 2000. The sum of its digit is 20. Only the digits in the ones place and hundreds place
jeka94
He wrote the number 1892, because:

The number needs to be less than 2000, with four digits. Because the first is half the last, it means that the number must be 1??2.

These two numbers add up to 3, and all together, they need to add to 20. 20-3=17. The remaining numbers need to add to 17.

The only two single digit numbers that can add to 17, are 8 and 9. Therefore, the number must either be 1892 or 1982.

The second digit needs to be even, meaning that the number has to be 1892.

I hope this helps.
7 0
3 years ago
Read 2 more answers
Someone smart help me please
wolverine [178]
(-5,2) concave up

Hope this helps :)
6 0
3 years ago
Which of the following addition problems yields a sum that is an irrational number? Select TWO that apply. 23+97 2√+2√ 32+25√ 4√
GuDViN [60]

Answer:

28n 72uwbs jsjsbkajskld

5 0
3 years ago
What is the function written in vertex form?
lys-0071 [83]

Answer:

The answer in the procedure

Step-by-step explanation:

The question does not present the graph, however it can be answered to help the student solve similar problems.

we know that

The equation of a vertical parabola into vertex form is equal to

f(x)=a(x-h)^{2}+k

where

a is a coefficient

(h,k) is the vertex

If the coefficient a is positive then the parabola open up and the vertex is a minimum

If the coefficient a is negative then the parabola open down and the vertex is a maximum

case A) we have

f(x)=3(x+4)^{2}-6

The vertex is the point (-4,-6)

a=3

therefore

The parabola open up, the vertex is a minimum

case B) we have

f(x)=3(x+4)^{2}-38

The vertex is the point (-4,-38)

a=3

therefore

The parabola open up, the vertex is a minimum

case C) we have

f(x)=3(x-4)^{2}-6

The vertex is the point (4,-6)

a=3

therefore

The parabola open up, the vertex is a minimum

case D) we have

f(x)=3(x-4)^{2}-38

The vertex is the point (4,-38)

a=3

therefore

The parabola open up, the vertex is a minimum

4 0
3 years ago
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