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mariarad [96]
3 years ago
15

Find the radius of each circle. 17) circumference = 62.8 mi

Mathematics
1 answer:
kirill [66]3 years ago
3 0

IM IN 6TH GRADE. I DUNNO?

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Businesses in a country are listed by size: small, medium, and large. Explain why business size is an example of an ordinal-scal
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Answer: C. The size of a business is​ ordinal-scaled because it has values that can be used as an order or rank of a categorical variable.

Step-by-step explanation: Ordinal variables are simply categorical in nature just like nominal variables, however, the difference exists in the fact that ordinal labels posses an ordered rank or level unlike nominal variables. Though the extent or width of the difference between these labels cannot be ascertained. In the scenario above, size of businesses are labeled qualitatively with labels such as : small, medium and large. This labels depicts and follow a certain order with small being the least, then medium, then large. Telling us large businesses are superior in size to small and medium and medium is superior to large. Though the extent of the difference cannot be accurately ascertained.

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Ella has gold,silver,and copper wire for stringing beads.she has1 1\2ft.of gold wire,2 1\3ft.of silver wire,and3 3\4ft.of copper
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If you start with 60% sunny days and after 200 days it decrease by 50%. How many days of the 200 were sunny days
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2 years ago
Approximate the square root to the nearest whole number 142
slamgirl [31]
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7 0
2 years ago
30 POINTS I WILL GIVE U BRAINLIEST AND THANKS AND 5 STARS please help this is very important this is a big part of my grade
mars1129 [50]

Answer:

1.\:2^x=64, x=\boxed{6},\\2.\:x=\left(\frac{2}{3}\right)^3,x=\boxed{\frac{8}{125}}\\3.\:3\cdot (3^4)=3^x, x=\boxed{5}\\4.\:\frac{16}{25}=x^2,x=\boxed{\frac{4}{5}},

Step-by-step explanation:

1.\\\\2^x=64,\\\log 2^x=\log64,\\x\log 2=\log 64,\\x=\frac{\log 64}{\log 2}=\boxed{6}

2.\\x=\left(\frac{2}{5}\right)^3=\frac{2^3}{5^3}=\boxed{\frac{8}{125}}

3. This problem incorporates an exponent property.

Exponent property used: a^b\cdot a^c=a^{(b+c)}, yielding an answer of \boxed{5}

4.\\\\\frac{16}{25}=x^2,\\x=\sqrt{\frac{16}{25}}=\frac{\sqrt{16}}{\sqrt{25}}=\boxed{\frac{4}{5}}

3 0
3 years ago
Read 2 more answers
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