Let r(cos O + i sin O) be a cube root of 125(cos 288 + i sin 288)
then
r^3(cos O + i sin O)^3 = 125(cos 288 + i sin 28)
so r^3 = 125 and cos 3O + i sin 3O = cos 288 + i sin 288
so r = 5 and 3O = 288 + 360p and O = 96 + 120p
so one cube root is 5 (cos 96 + i sin 96)
Im a little rusty at this stuff Its been a long time.
Im not sure of the other 2 roots
sorry cant help you any more
The correct answer is:
2u-v=7(5i-3j)
Therefore, 5, and 3 go inside the box.
If that is a rhombus as it says it is, then the diagonals are perpendicular to one another, meaning where they meet, they form right angles. Therefore, angle x is a 90 degree angle.
Answer:
using your brain you have to find it on your own
