You can use the method of pythagorean theorem.
a² + b² = c²
or in your case, 14² + 15² = x²
14² = 14 * 14 = 196
15² = 15 * 15 = 225
196 + 225 = 451
√451 = 21.237
or 21.23676058159
*I rounded to the nearest thousands place
X=-5.5 the other zero would be x=-0.5 but that’s not an option.
Answer:
30.49 m
Step-by-step explanation:
To obtain the maximum height, we solve for the value x when dy/dx = 0.
Since, y = -5x² + 40x + 20
dy/dx = d[-5x² + 40x + 20]/dx
dy/dx = -10x + 40
Since dy/dx = 0,
-10x + 40 = 0
-10x = -40
x = -40/-10
x = 4
Substituting x = 4 into the equation for y, we have
y = -5x² + 40x + 20
y = -5(4)² + 40(4) + 20
y = -5(16) + 160 + 20
y = -80 + 160 + 20
y = 80 + 20
y = 100 ft
Since y is in feet, we convert to meters.
Since 1 m = 3.28 ft, 100 ft = 100 ft × 1 m/3.28 ft = 30.49 m
So, the maximum height, in meters reached by the projectile is 30.49 m
Answer:
20cm
Step-by-step explanation:
A=hb/2
h=5cm
b=8cm
A=(5*8)/2
A=40/2
A=20
No because...
3(d+12) =8
Distribute the 3.
3d+36=8
Subtract the 36.
3d = -28
Divide by 3 to isolate d.
d = -28/3 or 9.33
