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2 years ago

19, 25, 31, 19, 34, 22, 31, 34Mean:Median:Mode:Range:

Mathematics

2 answers:

Anon25 [30]2 years ago

8 0

Answer:

mean: 27

median: 27

mode: 19, 31, 34

range: im very bad at finding this srry

Step-by-step explanation:

pls tell me if im wrong

Ksju [112]2 years ago

3 0

Mean- 26.875
Median- 28
Mode- 34,19,31
Range- 15

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Find three real numbers x, y, and z whose sum is 6 and the sum of whose squares is as small as possible. g

mart [117]

We're minimizing $x^2+y^2+z^2$ subject to $x+y+z=6$ . Using Lagrange multipliers, we have the Lagrangian

$L(x,y,z,\lambda)=x^2+y^2+z^2+\lambda(x+y+z-6)$

with partial derivatives

$\begin{cases}L_x=2x+\lambda\\L_y=2y+\lambda\\L_z=2z+\lambda\\L_\lambda=x+y+z-6\end{cases}$

Set each partial derivative equal to 0:

$\begin{cases}2x+\lambda=0\\2y+\lambda=0\\2z+\lambda=0\\x+y+z=6\end{cases}$

Subtracting the second equation from the first, we find

$2x-2y=0\implies x=y$

Similarly, we can determine that $x=z$ and $y=z$ by taking any two of the first three equations. So if $x=y=z$ determines a critical point, then

$x+y+z=3x=6\implies x=y=z=2$

So the smallest value for the sum of squares is $2^2+2^2+2^2=12$ when $(x,y,z)=(2,2,2)$ .

8 0

2 years ago

In a sewage treatment plant, a large concrete tank initially contains 440,000 liters of liquid and 10,000 kg of fine suspended s

viva [34]

Answer:

$Concentration = 8.26kg/m^3$

Step-by-step explanation:

Given

$V = 440000L$ --- volume of tank

$m = 10,000 kg$ --- solid mass

$r = 40000L/hr$ --- outflow rate

Required

Determine the concentration at the end of 4 hours

First, calculate the amount of liquid that has been replaced at the end of the 4 hours.

$Amount = r * Time$

$Amount = 40000L/hr * 4hr$

$Amount = 40000L * 4$

$Amount = 160000L$

This implies that, over the 4 hours; The tank has 160000 liters of liquid out of 440000 liters were replaced

Calculate the ratio of the liquid replaced.

$Ratio = \frac{Amount}{Volume}$

$Ratio = \frac{160000L}{440000L}$

$Ratio = \frac{16}{44}$

$Ratio = \frac{4}{11}$

Next, calculate the amount of solid left.

$Amount (Solid)= Ratio * m$

$Amount (Solid)= \frac{4}{11} * 10000kg$

$Amount (Solid)= \frac{40000}{11}kg$

$Amount (Solid)= 3636kg$

Lastly, the concentration is calculated as:

$Concentration = \frac{Amount (Solid)}{Volume}$

$Concentration = \frac{3636kg}{440000L}$

Convert L to cubic meters

$Concentration = \frac{3636kg}{440000* 0.001m^3}$

$Concentration = \frac{3636kg}{440m^3}$

$Concentration = 8.26kg/m^3$

3 0

2 years ago

^ need help !!!!!!!!!!!!!!!!!!!!

elena-14-01-66 [18.8K]

First set up the equation to find answer: y=7-x. Then add it to the variable. 3x-1(7-x)=1. So that makes it 3x+-7+-1=1. Add like terms -7+-1=-8, so 3x+-8=1. Now to find x just switch the 8 to the other side. So you end up with 3x=9 since when you take away a number from one side you need to use the opposite value so adding 8 to -8 will cancel it out, then add it to the other, then just divide. 9/3=3, from here just substitute to find y. y=7+3. y=10. The answer is x=2 and y=5. I hope I helped!

5 0

2 years ago

Read 2 more answers

The top option, "meat lovers", received 12 votes. Was this majority of the votes?

ICE Princess25 [194]

Answer:

Step-by-step explanation:

if the number of votes is 25, 12 is not majority

but if the number is 23 then 12 is majority

6 0

2 years ago

3. A mysterious metal medallion has a mass of 3,088 grams. Water is poured into a graduated glass container with a 10-by-10 cm s

Gekata [30.6K]

Step-by-step explanation:

Volume of displaced water = (10cm)(10cm)(1.6cm)

= 160 cm^3

density = mass/vol of displaced water

= 3088 grams/160 cm^3

= 19.3 g/cm^3

P.S. This is most likely a pure gold medallion.

6 0

2 years ago

19, 25, 31, 19, 34, 22, 31, 34Mean:Median:Mode:Range:​

19, 25, 31, 19, 34, 22, 31, 34Mean:Median:Mode:Range: