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Vanyuwa [196]
3 years ago
13

What is the area of square UVWX?Area = ​

Mathematics
1 answer:
guapka [62]3 years ago
8 0

Answer:

Area = 64

Step-by-step explanation:

area of a square = side^{2}

side length = 8

8^{2} = 64

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A coffee business sells a pound of coffee for $ 9.75. Monthly expenses are $ 4,500 plus $ 4.25 for every pound of coffee sold. a
hram777 [196]

Answer:

a. IT = 9.75 * X

b. GT = 4500 + 4.25 * X

c. G = 9.75 * X - 4500 - 4.25 * X

Step-by-step explanation:

With the data of the statement we can get a function. Let X be the number of pounds sold.

to. Monthly income

IT = 9.75 * X

b. Monthly expenses

GT = 4500 + 4.25 * X

c. Monthly Earnings (Monthly Income - Monthly Expenses)

G = 9.75 * X - (4500 + 4.25 * X)

G = 9.75 * X - 4500 - 4.25 * X

4 0
3 years ago
The mark in a subject for 12 students are as follows 31`, 37 ,35,38 ,42 ,23,17,18 ,35,25, 35,29
just olya [345]

Answer:

Mean (Average): 30.416666666667

Median: 33

Range: 25

Mode: 35, appeared 3 times

Step-by-step explanation:

8 0
2 years ago
Which is the perimeter of the triangle below?<br>13/24 foot<br>22/24 foot<br>28/24 foot​
tensa zangetsu [6.8K]

Answer:

c.  22/24

Step-by-step explanation:

perimeter = 3/8 + 3/8 + 1/6

perimeter = 22/24 or 11/12

3 0
3 years ago
The radius of a circle is 18 meters. What is the circle's area?
ankoles [38]

Answer:

200.96 sq. meters.

Step-by-step explanation:

The formula for the area of a circle is \pi r^(2). To solve for the area, use the given values, pi is 3.14 and the radius is 18. This gives you the new equation of (3.14)(18)^2. Solve algebraically, first raising the radius to the power of 2, and then multiplying.

5 0
3 years ago
The limit as h approaches 0 of (e^(2+h)-e^2)/h is ?
Whitepunk [10]
<span>If you plug in 0, you get the indeterminate form 0/0. You can, therefore, apply L'Hopital's Rule to get the limit as h approaches 0 of e^(2+h),
which is just e^2.
</span><span><span><span>[e^(<span>2+h) </span></span>− <span>e^2]/</span></span>h </span>= [<span><span><span>e^2</span>(<span>e^h</span>−1)]/</span>h

</span><span>so in the limit, as h goes to 0, you'll notice that the numerator and denominator each go to zero (e^h goes to 1, and so e^h-1 goes to zero). This means the form is 'indeterminate' (here, 0/0), so we may use L'Hoptial's rule:
</span><span>
=<span>e^2</span></span>
3 0
3 years ago
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