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ratelena [41]
4 years ago
11

Solve: 12 Superscript x squared + 5 x minus 4 Baseline = 12 Superscript 2 x + 6

Mathematics
2 answers:
Butoxors [25]4 years ago
7 0

Answer:

C. x=2, X=-5

Step-by-step explanation:

loris [4]4 years ago
4 0

Answer:

x =  - 5

or

x = 2

Step-by-step explanation:

We want to solve ;

{12}^{ {x}^{2}  + 5x - 4}  =  {12}^{2x + 6}

We equate the exponents, because is the same on both sides.

{x}^{2}  + 5x - 4 = 2x + 6

We group and rewrite in standard form to get:

{x}^{2}  + 5x - 2x - 4 - 6 = 0

{x}^{2}  + 3x- 10= 0

{x}^{2}  - 2x + 5x - 10 = 0

x(x - 2) + 5(x - 2) = 0

(x + 5)(x - 2) = 0

x =  - 5 \: or \: x = 2

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