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FinnZ [79.3K]
4 years ago
6

Create an example of a situation where there is a negative cash flow.

Mathematics
2 answers:
nataly862011 [7]4 years ago
7 0
When say your expenses are $400 a month but your income is only $350 a month that is -$50 every month so in that case you aren't getting a positive cash flow (which would be making more money than your expenses) So you must be getting a negative cash flow in which you are losing money and going into debt.
dedylja [7]4 years ago
4 0

Negative cash flow does not necessarily means loss, and may be due only to a mismatch of expenditure and income.If there is any company that has to pay a bill but is not able to pay the bills and has to borrow then  this is a case of negative cash flow.It means the company is spending more than it is earning.Companies take loan to fulfill negative cash flow.

For example : Company A has to pay $20000 as labor charges and has only $10879  in its account. We say the company has negative cash flow.


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The reflection of point S across the y-axis is point ___. The reflection of point Q across the x-axis and the y-axis is point __
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Answer:

The reflection of point S across the y-axis is point <u>   V   </u>. The reflection of point Q across the x-axis and the y-axis is point <u>   V   </u>, whose coordinates are ( <u>   -5  </u> , <u>   -5.5   </u>).

===============================================

Explanation:

Point S is exactly 5 units away from the vertical y axis. Move from point S(5,-5.5) to the location (0,-5.5); ie move 5 units to the left. Then move another 5 units to the left to land on point V(5, -5.5)

Points V and S are the same distance away from the mirror line.

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Reflecting point Q over the x axis lands us on point S. This time we move down 5.5 units to get to the x axis. Then move another 5.5 units to arrive at point S. As discussed above, point S then will reflect over the y axis to get to point V.

Side note: Combining two reflections produces a rotation. So effectively, going from Q to V is a rotation of 180 degrees.

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See below

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Using PEDMAS:

O Subtract 12 from the product of 5 and 3, then multiply by 87​

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