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2 years ago

9

Large Reusable bottles cost four dollars more than small ones eat large bottles cost $24 less than small ones how much does one

small bottle cost

1 answer:

madam [21]2 years ago

7 0

Answer:

$20

Step-by-step explanation:

The large ones cost $4 more so what you would do is to subtract that $4 from the $24.

24-4=20

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HELP!! PLEASEE!

amm1812

Answer:

A

Step-by-step explanation:

The blue graph, g(x), is shifted down 8 units.

So the answer is f(x)-8 which is A

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2 years ago

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40 points!!! please tell me how to do it not what the answer is :D

Julli [10]

Answer:

C

Step-by-step explanation:

You first distribute within the parentheses which is -(-z-2). This is going to make everything positive as everything in the parentheses is negative. You should get z+2. Next, you plug that back in. It should be-3z+z+2. You simplify to get -2z+2. Hope this helps!

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2 years ago

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Candice drives a total of 48 miles each day to work and get back home. She works five days a week. Her car gets 21 miles per gal

slega [8]

Answer:

Total gallon of fuel used = $11.428$ gallons

Step-by-step explanation:

Given -

The total distance travelled by car in one gallon of gas = 21 miles

Total distance travelled each day = 48 miles

Number of days days in a week in which Candice drive is 5 days

Total miles travelled per week = $48*5$ = 240 miles

Total gallon of fuel used = $\frac{240}{21} = 11.428$ gallons

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2 years ago

What is wrong with this problem. 2(n +3) = 2n +3

LekaFEV [45]

Steps to solve:

2(n + 3) = 2n + 3

~Distribute left side

2n + 6 = 2n + 3

~Subtract 6 to both sides

2n = 2n - 3

~Subtract 2n to both sides

n = -3

Best of Luck!

7 0

2 years ago

In a random sample of 30 people who rode a roller coaster one day, the mean wait time is 46.7 minutes with a standard deviation

Rainbow [258]

Answer: C. $(29,\ 37.8)$

Step-by-step explanation:

The confidence interval for difference of two population mean is given by :-

$\overline{x}_1-\overline{x}_2\pm z_{\alpha/2}\sqrt{\dfrac{s_1^2}{n_1}+\dfrac{s_2^2}{n_2}}$

Given : Level of significance : $1-\alpha:0.99$

Then , significance level : $\alpha: 1-0.99=0.01$

Critical value : $z_{\alpha/2}=z_{0.005}=2.576$

$n_1=30\ ;\ n_2=50\\\\\overline{x}_1=46.7\ ;\ \overline{x}_2=13.3\\\\s_1=9.2\ ;\ s_2=1.9$

$46.7-13.3\pm(2.576)\sqrt{\dfrac{9.2^2}{30}+\dfrac{1.9^2}{50}}\approx33.4\pm4.38=(29.02\ ,37.78)\approx(29,\ 37.8)$

Hence, a 99% confidence interval for the difference between the mean wait times of everyone who rode both rides $(29,\ 37.8)$

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3 years ago