The data is qualitative (statement is incorrect)
The data is skewed right (statement is correct)
There were 31 people at the party (statement is correct)
There were children at the party (statement is incorrect)
The most common age of the attendees is 13 years old (statement incorrect - there is no way to tell that the most common age is 13 years old)
The majority of people at the party is less than 61 years old (statement correct)
3.88888=3.88888/1=38.8888888
so lets ssay our repeating decimal = a fraction x
x=3.888 is true
multiply by 10
10x=38.8888
now subtract fir frist eqation from second
10x-x=38.8888-3.888888
9x=35
divide both sides by 9
x=35/9
x=3 and 7/9
anser is 3.88=3 and 7/9
0^2/0^9 = 0/0, therefore your answer is 1/1 considering that it is a fraction that is 100%, but if you divide 0 by 0, according to Keith’s theory you should have an endless number aka Infinity.
The correct answer is C) -15.
Anyways, I hope you have a wonderful evening :)
Answer:
Yes, both np and n(1-p) are ≥ 10
Mean = 0.12 ; Standard deviation = 0.02004
Yes. There is a less than 5% chance of this happening by random variation. 0.034839
Step-by-step explanation:
Given that :
p = 12% = 0.12 ;
Sample size, n = 263
np = 263 * 0.12 = 31.56
n(1 - p) = 263(1 - 0.12) = 263 * 0.88 = 231.44
According to the central limit theorem, distribution of sample proportion approximately follow normal distribution with mean of p = 0.12 and standard deviation sqrt(p*(1 - p)/n) = sqrt (0.12 *0.88)/n = sqrt(0.0004015) = 0.02004
Z = (x - mean) / standard deviation
x = 22 / 263 = 0.08365
Z = (0.08365 - 0.12) / 0.02004
Z = −1.813872
Z = - 1.814
P(Z < −1.814) = 0.034839 (Z probability calculator)
Yes, it is unusual
0.034 < 0.05 (Hence, There is a less than 5% chance of this happening by random variation.
