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Amanda [17]
3 years ago
9

Large Reusable bottles cost four dollars more than small ones eat large bottles cost $24 less than small ones how much does one

small bottle cost
Mathematics
1 answer:
madam [21]3 years ago
7 0

Answer:

$20

Step-by-step explanation:

The large ones cost $4 more so what you would do is to subtract that $4 from the $24.

24-4=20

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professor190 [17]
What do bones do?

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3.) They produce blood cells in bone marrow. 

4.) They allow us to move. 

5.) They store minerals and some fats. 

I hope this helps!


6 0
3 years ago
Helphelphelphelphelphelppppppp
n200080 [17]

Answer:

Step-by-step explaSimplify the equation by finding the square root of both sides. √x2=x √0=0. x=0. Check: 02=0.

5 0
3 years ago
What does 4x-2y=2 equal to step by step
podryga [215]

Answer:

y = 2x - 1

Step-by-step explanation:

4x - 2y = 2

So I'm assuming that your goal is to solve for the value of y in terms of x

First: the whole equation can be divided by 2

2x - y = 1

Second: subtract 2x from both sides

-y = -2x + 1

Third: divide each side by -1

y = 2x - 1

Done! I would appreciate Brainliest but no worries.

5 0
3 years ago
Read 2 more answers
Joey fixes bicycles and charges a shop fee of $15 and $10 per hour for time worked. If t is the number of hours worked and C is
Bezzdna [24]
I beleive it is a because both variable could change
3 0
3 years ago
Let f(x,y,z) = ztan-1(y2) i + z3ln(x2 + 1) j + z k. find the flux of f across the part of the paraboloid x2 + y2 + z = 3 that li
Sophie [7]
Consider the closed region V bounded simultaneously by the paraboloid and plane, jointly denoted S. By the divergence theorem,

\displaystyle\iint_S\mathbf f(x,y,z)\cdot\mathrm dS=\iiint_V\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV

And since we have

\nabla\cdot\mathbf f(x,y,z)=1

the volume integral will be much easier to compute. Converting to cylindrical coordinates, we have

\displaystyle\iiint_V\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV=\iiint_V\mathrm dV
=\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}\int_{z=2}^{z=3-r^2}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta
=\displaystyle2\pi\int_{r=0}^{r=1}r(3-r^2-2)\,\mathrm dr
=\dfrac\pi2

Then the integral over the paraboloid would be the difference of the integral over the total surface and the integral over the disk. Denoting the disk by D, we have

\displaystyle\iint_{S-D}\mathbf f\cdot\mathrm dS=\frac\pi2-\iint_D\mathbf f\cdot\mathrm dS

Parameterize D by

\mathbf s(u,v)=u\cos v\,\mathbf i+u\sin v\,\mathbf j+2\,\mathbf k
\implies\mathbf s_u\times\mathbf s_v=u\,\mathbf k

which would give a unit normal vector of \mathbf k. However, the divergence theorem requires that the closed surface S be oriented with outward-pointing normal vectors, which means we should instead use \mathbf s_v\times\mathbf s_u=-u\,\mathbf k.

Now,

\displaystyle\iint_D\mathbf f\cdot\mathrm dS=\int_{u=0}^{u=1}\int_{v=0}^{v=2\pi}\mathbf f(x(u,v),y(u,v),z(u,v))\cdot(-u\,\mathbf k)\,\mathrm dv\,\mathrm du
=\displaystyle-4\pi\int_{u=0}^{u=1}u\,\mathrm du
=-2\pi

So, the flux over the paraboloid alone is

\displaystyle\iint_{S-D}\mathbf f\cdot\mathrm dS=\frac\pi2-(-2\pi)=\dfrac{5\pi}2
6 0
3 years ago
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