Question

The mean of six numbers is 45. Four of the numbers are 40, 38, 46, and 51. If the remaining two numbers are I. The ratio of 2:3, find the two numbers.

Answer 1

Answer:

The numbers are 38 and 57

Step-by-step explanation:

Let

x-----> the missing smaller number

y----> the missing larger number

we know that

$45=\frac{40+38+46+51+x+y}{6} \\ \\270=175+x+y$

$x+y= 95$ -----> equation A

$\frac{x}{y}=\frac{2}{3}$

$x=\frac{2}{3}y$ -----> equation B

substitute equation B in equation A and solve for y

$\frac{2}{3}y+y= 95$

$\frac{5}{3}y= 95$

$y=95*3/5=57$

Find the value of x

$x=\frac{2}{3}(57)=38$