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3 years ago

Find the time between 12:20 and 23:0 the same day

1 answer:

5 0

I'm guessing you are using military time.

Note, 23:00 is the same as 11:00 pm, and 12:20 is the same as 12:20 pm

Also note: 1 hour = 60 minutes

1) Change 1 hour inside 23:00 to minutes

23:00 = 22:60

Subtract

22:60 - 12:20 = 10:40

The time between 12:20 and 23:00 is 10 hours and 40 minutes

hope this helps

You might be interested in

Use a proportion with sides AB and RS to find the scale factor of ABD to RST.

Dmitry_Shevchenko [17]

Answer:

$\boxed{3:1}$

Step-by-step explanation:

Similar triangles are those whose shape is the same, but they don't necessarily have the same size. However, the corresponding sides of the triangles are in the same length ratio. In this exercise, we know all the sides of triangle ΔABC and an only side of the triangle ΔRST. To find the scale factor, we must compute the following:

$\frac{AB}{RS}=\frac{18}{6}=3 \\ \\ Scale \ factor \\ \boxed{3:1}$

Finally, the other sides of the tingle ΔRST can be found by dividing each side of triangle ΔABC by 3 as follows:

$ST=\frac{15}{3}=5 \\ \\ RT=\frac{9}{3}=3$

4 0

4 years ago

I need help it’s geometry it’s due today at 11:59 pm Texas time

LuckyWell [14K]

Answer:

to be parallel

slope should be equal

for first question

y=1/3X +2

comparing with y=m1x+c

slope = 1/3

similarly for second equation

y=1/3x -4

comparing with y=m2x + c

m2= 1/3

since m1=m2

lines are parallel

8 0

3 years ago

Express the product of z1 and z2 in standard form given that <img src="https://tex.z-dn.net/?f=z_%7B1%7D%20%3D%20-3%5Bcos%28%5Cf

Marta_Voda [28]

Answer:

Solution : 6 + 6i

Step-by-step explanation:

$-3\left[\cos \left(\frac{-\pi }{4})\right+i\sin \left(\frac{-\pi }{4}\right)\right]\cdot \:2\sqrt{2}\left[\cos \left(\frac{-\pi }{2}\right)+i\sin \left(\frac{-\pi }{2}\right)\right]$

This is the expression we have to solve for. Now normally we could directly apply trivial identities and convert this into standard complex form, but as the expression is too large, it would be easier to convert into trigonometric form first ----- ( 1 )

( Multiply both expressions )

$-6\sqrt{2}\left[\cos \left(\frac{-\pi }{4}+\frac{-\pi \:\:\:}{2}\right)+i\sin \left(\frac{-\pi \:}{4}+\frac{-\pi \:\:}{2}\right)\right]$

( Simplify $\left(\frac{-\pi }{4}+\frac{-\pi }{2}\right)$ for both $\cos \left(\frac{-\pi }{4}+\frac{-\pi }{2}\right)$ and $i\sin \left(\frac{-\pi }{4}+\frac{-\pi }{2}\right)$ )

$\left(\frac{-\pi }{4}+\frac{-\pi }{2}\right)$ = $\left(-\frac{3\pi }{4}\right)$

( Substitute )

$-6\sqrt{2}\left(\cos \left(-\frac{3\pi }{4}\right)+i\sin \left(-\frac{3\pi }{4}\right)\right)$

Now that we have this in trigonometric form, let's convert into standard form by applying the following identities ----- ( 2 )

sin(π / 4) = √2 / 2 = cos(π / 4)

( Substitute )

$-6\sqrt{2}\left(-\sqrt{2} / 2 -i\sqrt{2} / 2 )$

= $-6\sqrt{2}\left(-\frac{\sqrt{2}}{2}-\frac{\sqrt{2}}{2}i\right)$ = $-\frac{\left(-\sqrt{2}-\sqrt{2}i\right)\cdot \:6\sqrt{2}}{2}$

= $-3\sqrt{2}\left(-\sqrt{2}-\sqrt{2}i\right)$ = $-3\sqrt{2}\left(-\sqrt{2}\right)-\left(-3\sqrt{2}\right)\sqrt{2}i$

= $3\sqrt{2}\sqrt{2}+3\sqrt{2}\sqrt{2}i:\quad 6+6i$ - Therefore our solution is option a.

4 0

4 years ago

Carol has a small copy of a painting. The dimensions of her copy are shown at right. The scale of the copy is 0.5 inches : 12 ce

larisa [96]

The complete question in the attached figure

we know that
[scale]=0.5/12
[scale]=[copy of a painting]/[original painting]

dimensions copy of a painting--------------> 1.75 in x 5.25 in

for 1.75 in
[original painting]=[copy of a painting]/[scale]
[original painting]=[1.75]/[(0.5/12)]=42 cm

for 5.25 in
[original painting]=[copy of a painting]/[scale]
[original painting]=[5.25]/[(0.5/12)]=126 cm

the answer Part A) is
the dimensions of the original painting are 42 cm x 126 cm

Part B)
Find the area of the original painting.
[area of the original painting]=42*126=5292 cm²

the answer Part B) is
area of the original painting is 5292 cm²

Part C)
One centimeter is equal to approximately 0.033 foot. Find the dimensions of the original painting in feet.

the dimensions of the original painting are 42 cm x 126 cm
then

for 42 cm
if 1 cm----------------> 0.033 ft
42 cm----------------> X
X=42*0.033=1.386 ---------> 1.386 ft

for 126 cm
if 1 cm----------------> 0.033 ft
126 cm----------------> X
X=126*0.033=4.158 --------> 4.158 ft

the answer Part C) is
the dimensions of the original painting in feet are 1.386 ft x 4.158 ft

Part D) Find the area of the painting in square feet. Round to the nearest thousands.

the dimensions of the original painting in feet are 1.386 ft x 4.158 ft
{Area original painting in feet]=1.386*4.158=5.763 ft²

the answer part C) is
the area original painting in feet is 5.763 ft²

3 0

4 years ago

I need help plz answer before Monday 26th

IRISSAK [1]

The first one is 3 8/10 are not rotten because 5 3/10- 1 5/10 = 3 8/10

The second one needs information on the strawberries which it dosen't show on the picture.

Hope this helped a bit.

7 0

3 years ago