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olga55 [171]
3 years ago
8

Solve the equation 3x+2=x+4(x+2)

Mathematics
2 answers:
Studentka2010 [4]3 years ago
8 0

3x+2 = x+4(x+2)  

distribute

3x+2 = x+4x+8

combine like terms

3x+2 = 5x +8

subtract 3x from each side

2 = 2x +8

subtract 8 from each side

-6 = 2x

divide by 2

-3 = x

ikadub [295]3 years ago
8 0
6=-2x is da answer my dude
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Find the 7th term of the geometric sequence<br> 7, 24.5, 85.75, ...
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Answer:

12,867.859375

Step-by-step explanation:

24.5/7 = 3.5

Geometric sequence

A_n = 7 * (3.5)^(n - 1)

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4 0
3 years ago
The function f(x) = x is translated using the rule (x, y) - (x - 6, y + 9) to create A(x).
anyanavicka [17]

<em>It seems the correct function you need to mention is f(x) = sqrt x</em>

<em>so, I am assuming </em>f(x) = \sqrt{x}<em> and will solve the question based on it.</em>

Answer:

Check the explanation

Step-by-step explanation:

Given the function

f(x) = \sqrt{x}

As the function is translated according to the rule

  • (x, y) → (x - 6, y + 9)

Translation of the function f(x) = \sqrt{x} 6 units to the left will bring the function

g(x) = \sqrt{x+6}

Translation of the function  g(x) = \sqrt{x+6}  9 units up will bring the function

A\left(x\right)=\sqrt{x+6}+9

Determining the range of A\left(x\right)=\sqrt{x+6}+9

  • As we know that the range is the set of dependent values for which the function is defined.

\mathrm{The\:range\:of\:an\:radical\:function\:of\:the\:form}\:c\sqrt{ax+b}+k\:\mathrm{is}\:\:f\left(x\right)\ge \:k

k=9

f\left(x\right)\ge \:9

so

\mathrm{Range\:of\:}\sqrt{x+6}+9:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\ge \:9\:\\ \:\mathrm{Interval\:Notation:}&\:[9,\:\infty \:)\end{bmatrix}

Therefore, the expression describes the range of A(x) will be:

f\left(x\right)\ge \:\:9\:or\:y\:\ge \:\:\:9

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3 years ago
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inna [77]
The correct answer is130
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