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mr_godi [17]
3 years ago
10

For a wedding the bride must select 4 bridesmaids from her 6 closest friends and must arrange them in order for the ceremony. Ho

w many arrangements of 4 bridesmaids from her 6 closest friends?
Asap will give brainliest
Mathematics
1 answer:
liraira [26]3 years ago
6 0
She will only 4 arrangements for each bridesmaid
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Please help I will give you 20 points and brainlest if you do
Alexxx [7]

Answer:

1/100

10/100 or 1/10

90/100 or 9/10

i believe this is what it means

Step-by-step explanation:


7 0
3 years ago
Xorlali neeas a number with an 8 in the ten thousands place. Which number can he choose? A. 8,021 C. 8,214,617 B. 16,816 D. 781,
Assoli18 [71]

Answer:

The answer to your questions is letter D

Step-by-step explanation:

We need to look for a number that has an 8 in the ten thousands that means a number after in the fifth position after the decimal point

A. 8,021          this number only has 4 numbers and we need five, then is incorrect.

C. 8,214,617   this number has a number 1 in the fifth position then is incorrect

B. 16,816        this number has a number 1 in the fifth position then is incorrect

D. 781,200      this number has an 8 in the fifth position then is the one we are looking for

7 0
3 years ago
What is the range of f(x) ?<br> A<br> B<br> C<br> D<br> Graph and answer choices are above
aksik [14]
The range should be B
7 0
3 years ago
Using the quadratic formula to solve x2 = 5 - x, what are the values of x?
RideAnS [48]

Exact Form:

x

=

−

1

−

√

21

2

,

−

1

+

√

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8 0
3 years ago
A standard letter-sized piece of paper has a length and width of 8.5 inches by 11 inches.
den301095 [7]

Answer:

Area of the resulting rectangle = 23.375 inch²

Step-by-step explanation:

After 1 fold width or length reduces to half.

Area = Length x width

So after 1 fold area will reduce to half.

So we have

              \texttt{Area after n folds =}\frac{\texttt{Initial area}}{2^{\texttt{number of folds}}}

Initial area = 8.5 x 11 = 93.5 inch²

Here the paper were folded completely in half, length is reduced to half and width reduced to half, that is

Number of folds = 2

\texttt{Area after 2 folds =}\frac{\texttt{Initial area}}{2^{2}}\\\\\texttt{Area after 2 folds =}\frac{93.5}{4}=23.375inch^2

Area after 2 folds = 23.375 inch²

Area of the resulting rectangle = 23.375 inch²

8 0
3 years ago
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