Answer:
The boat traveling at 24 kph when John goes downstream.
Step-by-step explanation:
We are given the following in the question:
John has a boat that will travel at the rate of 15 kph in still water.
Let x be the speed of the current.
Speed of boat in upstream

Speed of water in downstream

Relation:

We have to find the speed of boat in downstream.
Time to travel upstream for 35 km = Time to travel 140 km downstream

Thus, speed of current is 9 kph.
Speed of boat in downstream = 15 + 9 = 24 kph.
Thus, the boat traveling at 24 kph when John goes downstream.
Answer:
Step-by-step explanation:
SOLVE FOR X
x∈R
SOLVE FOR Y
y∈R
Answer:
B
Step-by-step explanation:
If you start to ask after 10:00 am, a lot of people isn't drinking caffeine. And, were trying to figure out the average.
The x-value increases by a factor of 5 from 1.6 to 8 between the two points. Because the variation is inverse, the y-value must decrease by a factor of 5 between the two points.
6/5 = 1.2
The second point is (8, 1.2), corresponding to the 4th selection.
Step-by-step explanation:
1cm = 16 km
Distance between York and London = 23.1 cm
<em>Now the real distance between </em><em>York </em><em>and </em><em>London </em><em>=</em><em> </em><em>2</em><em>3</em><em>.</em><em>1</em><em> </em><em>*</em><em> </em><em>1</em><em>6</em>
<em>=</em><em> </em><em>3</em><em>6</em><em>9</em><em>.</em><em>6</em><em> </em><em>km </em>